Contents

WMA14 P4: full past-paper analysis, Oct 2020 to Jun 2026 with October 2026 predictions

Edexcel IAL Pure Mathematics 4 (WMA14). 18 papers, updated 4 October 2026.

Headline findings

WMA14 is highly predictable by topic: seven of the eleven topics scored marks in all 18 papers, and even the least regular, connected rates of change, scored in 13. The strongest single signal for October 2026 is a volume of revolution, because June 2026 was the first paper without one after 17 in a row.

  • Vectors are the largest topic at 10.7 marks a paper (range 8–16), and five routines cover almost every part: lines meeting, angle, foot of a perpendicular, area, reflection.
  • Close to 30 of the 75 marks need integration, spread across substitution, parts, partial fractions, volumes and differential equations.
  • LIATE picks u correctly in all 19 integration-by-parts integrals: logarithm 4, algebraic 11, and 4 ex-times-trig loops where either choice works.
  • Binomial opens 11 of the 18 papers, and since June 2022 the bracket has started with a number other than 1 in 11 of 13.
  • Question styles are shifting: gradient-condition follow-ups in implicit differentiation (7 of the last 13), rational parametric curves (4 of the 6 since June 2025), cross-topic proofs (5 of the last 9), and twice as many no-calculator notices since January 2025 (3.6 a paper, up from 1.85).
  • October-only pattern: all three improper partial-fraction questions fell in October papers (2020, 2021, 2024).
  • Grade boundary for reference: in October 2024 an A needed 52/75 and the a* 58/75 (Pearson).

Scope and method

This analysis covers every WMA14 paper from October 2020 to June 2026: 18 papers, 166 questions and 1,350 marks, each read with its mark scheme.

  • Sessions: October 2020; January, June and October of 2021 to 2025; January and June 2026. There are no gaps in that window.
  • One relabelled paper: the question paper labelled “2020 May” is printed June 2020, but its mark scheme is the October 2020 one (WMA14_01_2010_MS). It is treated here as October 2020.
  • Tagging: every question part was assigned to the skill its marks test, using the part marks printed on the paper. Every paper sums to exactly 75.
  • Mixed parts: where one part tests two skills (a volume finished by integration by parts, say), its marks went to the skill doing most of the work. Read per-topic mark figures as roughly ±2.
  • Technique detail (the choice of u in parts, the substitution, the binomial power, the form of a differential equation, the vector task) comes from each mark scheme’s main method, not from alternatives.
  • Eleven topic rows are used throughout: vectors, parametric equations, implicit differentiation, differential equations, volumes and areas, binomial expansion, integration by substitution, partial fractions, proof by contradiction, connected rates of change, and integration by parts.

Paper structure

Every paper is 75 marks over 8 to 11 questions (166 in all, 8.1 marks on average). Binomial expansion opens 11 of the 18 papers, and the last question is parametric, proof or a differential equation in 16 of 18.

Session Questions Question 1 (marks) Largest question (marks) Last question (marks) No-calculator notices
Jun 2026 8 Partial fractions, then binomial (9) Q7 parts + substitution (13) Q8 differential equation, algae (10) 4
Jan 2026 9 Binomial, find a and n (8) Q5 parametric (11) Q9 parametric volume (8) 2
Oct 2025 10 Binomial (2 + 5x)^−2 (7) Q9 parametric gradient + area (15) Q10 proof, odd squares (6) 4
Jun 2025 10 Implicit, tangent (8) Q9 volume, paperweight (12) Q10 proof, trig inequality (4) 4
Jan 2025 9 Volume of revolution (5) Q8 vectors and Q9 parametric (12 each) Q9 parametric, tangent meets curve again (12) 4
Oct 2024 10 Binomial (8 − 3x)^(−1/3) (6) Q8 vectors and Q9 differential equation (10 each) Q10 parametric area (8) 2
Jun 2024 9 Parts, ∫x cos 3x (5) Q5 parametric area + partial fractions (13) Q9 volume by substitution (9) 2
Jan 2024 9 Binomial (1 − 4x)^−3 (4) Q6 vectors (14) Q9 parametric (12) 0
Oct 2023 8 Binomial (2 − 5x)^−2 (5) Q8 parametric + volume (14) Q8, as largest 1
Jun 2023 8 Binomial (1/4 − x/2)^(−3/2) (9) Q8 parametric + volume (12) Q8, as largest 1
Jan 2023 9 Partial fractions, then binomial (9) Q7 balloon, differential equation + rates (12) Q9 proof, ∛3 irrational (8) 3
Oct 2022 11 Parametric to Cartesian (3) Q7 substitution + parts (12) Q11 implicit, cycle track (9) 3
Jun 2022 9 Binomial (3 + kx)^−2 (7) Q7 parametric (12) Q9 proof, n2 − 2 (4) 4
Jan 2022 9 Implicit, tangent (6) Q8 vectors and Q9 differential equation (11 each) Q9 differential equation (11) 1
Oct 2021 10 Implicit, normal (7) Q9 tank, rates + differential equation (10) Q10 proof, ∛2 irrational (6) 2
Jun 2021 9 Binomial √(1 + kx) (7) Q6 parametric and Q7 vectors (10 each) Q9 vectors + proof (8) 1
Jan 2021 10 Binomial √(1 − 20x) (7) Q10 partial fractions + differential equation (14) Q10, as largest 3
Oct 2020 9 Proof, n3 even (4) Q4 parametric and Q7 integration (12 each) Q9 differential equation, bacteria (9) 1
  • Question 1: binomial in 11 papers (twice preceded by partial fractions), implicit differentiation in 3 (Oct 2021, Jan 2022, Jun 2025), and once each proof, a parametric-to-Cartesian conversion, integration by parts and a volume.
  • Largest question: parametric work (including parametric areas and volumes) is the largest, or joint largest, in 9 papers; vectors in 5. The single biggest question in the set is October 2025 Q9 at 15 marks.
  • Last question: parametric in 6 papers, proof in 6 (Jun 2021’s vectors question ends in a proof part), a differential equation in 4, implicit and a volume once each.
  • Question sizes run from 2 marks (Jan 2021 Q3, no greatest odd integer) to 15. Papers with 8 questions (Jun 2023, Oct 2023, Jun 2026) carry more 10+ mark questions.
  • No-calculator notices count the “Solutions relying (entirely) on calculator technology are not acceptable” lines. They averaged 1.85 a paper from Oct 2020 to Oct 2024, and 3.6 a paper across the five papers since January 2025.

Marks by topic in every paper

Every topic scores in nearly every paper; vectors lead at 10.7 marks a paper

Marks per topic in each WMA14 paper, October 2020 to June 2026, sorted by average. Darker cells mean more marks; a dash means none. The outlined column is June 2026, the paper before October 2026.

TopicOct
20
Jan
21
Jun
21
Oct
21
Jan
22
Jun
22
Oct
22
Jan
23
Jun
23
Oct
23
Jan
24
Jun
24
Oct
24
Jan
25
Jun
25
Oct
25
Jan
26
Jun
26
Avg
Vectors1011139119108101014161012812101010.7
Parametric1274961211115812291291311119.1
Implicit79976897101097988109108.4
Differential equations911912116889951186667108.4
Volumes and areas101213477611763895898–7.4
Binomial87767786954468107866.8
Substitution6887687467565667376.2
Partial fractions63–833731131064685635.3
Proof4256544845444446554.6
Rates of change––7488–4–756644–374.1
Integration by parts35–353554545544–563.9
Tagged part by part from the 18 WMA14 question papers and mark schemes, October 2020 to June 2026

Read across a row for how steady a topic is, and down a column for one paper’s mix. Rates of change is missing from five papers, integration by parts from two (both times it sat inside a differential equation), and volumes and areas only from June 2026.

Binomial expansion

A binomial question appears in all 18 papers (6.8 marks on average, range 4–10), and it is Question 1 in 11 of them. Since June 2022 the bracket has started with a number other than 1 in 11 of 13 papers, so taking out an is now routine.

Session (question, marks) Expression Power n Take out an Tasks Validity asked
Jun 2026 (Q1b–c, 6) (2 + 11x)/((1 + x)(2 + 5x)) = 3/(1 + x) − 4/(2 + 5x) −1, twice Yes, 2^−1 Expand each fraction and add: 1 + 2x − 19x2/2 Yes, |x| < 2/5
Jan 2026 (Q1, 8) (1 + ax)^n = 1 − 4x + (24/5)x2 + px3 5/2, found No Two equations in a and n, then p Yes, |x| < 5/8
Oct 2025 (Q1, 7) (2 + 5x)^−2 −2 Yes, 1/4 4 terms; then a + bx + cx2 for a related fraction Yes, |x| < 2/5
Jun 2025 (Q8, 10) (4 + x)^(−1/2), then (4 − x)^(−1/2) −1/2 Yes, 1/2 3 terms; swap x for −x; multiply to a + bx2; x = 1 gives √135 No
Jan 2025 (Q3, 8) 6(4 + Ax)^(−1/2) = B − x/4 + Cx2 + … −1/2 Yes, 1/2 Find A = 2/3, B = 3, C = 1/32; then the x3 coefficient Yes, |x| < 6
Oct 2024 (Q1, 6) (8 − 3x)^(−1/3) −1/3 Yes, 1/2 4 terms; x = 2/3 gives a rational approximation to ∛6 No
Jun 2024 (Q8a, 4) (8 − 3x)^(4/3) 4/3 Yes, 16 Show 16 − 8x + x2/2 + x3/24, then used in a proof No
Jan 2024 (Q1, 4) (1 − 4x)^−3 −3 No Up to x3 No (given)
Oct 2023 (Q1, 5) (2 − 5x)^−2 −2 Yes, 1/4 4 terms Yes, |x| < 2/5
Jun 2023 (Q1, 9) (1/4 − x/2)^(−3/2) −3/2 Yes, 8 8 + 24x + 60x2 + 140x3; then a related expansion No (given)
Jan 2023 (Q1b, 6) (5x + 10)/((1 − x)(2 + 3x)) = 3/(1 − x) + 4/(2 + 3x) −1, twice Yes, 2^−1 Up to x2 Yes, |x| < 2/3
Oct 2022 (Q4, 8) (4 − x2)^(−1/2) −1/2 Yes, 1/2 First 4 non-zero terms; rational approximation for √3 Yes, |x| < 2
Jun 2022 (Q1, 7) (3 + kx)^−2 −2 Yes, 1/9 x2 coefficient = 3 × x coefficient gives k2 + 6k = 0, k = −6; x3 coefficient 32/9 No
Jan 2022 (Q2, 7) (1 + 4x3)^(1/3) 1/3 No First 3 non-zero terms (x0, x3, x6); x = 1/3 gives ∛31 No (given)
Oct 2021 (Q4, 6) (1 − 4x2)^(1/2) 1/2 No First 4 non-zero terms; x = 1/4 gives √3 ≈ 1.7324 No (given)
Jun 2021 (Q1, 7) (1 + kx)^(1/2) 1/2 No k = 1/4 from the x coefficient; A, B; √1.15 to 6 d.p. No
Jan 2021 (Q1, 7) (1 − 20x)^(1/2) 1/2 No 4 terms; x = 1/100 gives √5 as a/b No (given)
Oct 2020 (Q2, 8) (4 − 5x)^(−1/2), then (2 + kx)(…) −1/2 Yes, 1/2 3 terms; compare coefficients for k = −13/20, m = 49/128 No (given)
  • Powers: −1/2 four times, 1/2 three, −2 three, −1 twice (via partial fractions), and 1/3, −1/3, −3, −3/2, 4/3 and 5/2 once each. Positive integer powers never appear here; they belong to P2.
  • Unknown constants in 5 papers (Oct 2020, Jun 2021, Jun 2022, Jan 2025, Jan 2026). Jan 2026 is the hardest form: two unknowns, eliminated by dividing (na)2 into n(n − 1)a2.
  • Approximations in 7 papers, always a root: √5, √1.15, √3 twice, ∛31, ∛6, √135. Students must pick the x that turns the bracket into the target and check it is in range.
  • Validity is asked in 7 papers, including 4 of the last 5. The rest print the range in the stem.
  • Inner term in x2 or x3 (Oct 2021, Jan 2022, Oct 2022) changes “first n terms” into “first n non-zero terms” and doubles or triples the powers.
  • Near-repeat: Oct 2023 Q1 is (2 − 5x)^−2 and Oct 2025 Q1 is (2 + 5x)^−2.
  • Combined uses: partial fractions then expansion (Jan 2023, Jun 2026), a product with a polynomial (Oct 2020), a product of two expansions (Jun 2025), and an expansion feeding a proof (Jun 2024).

Partial fractions

Partial fractions appear in all 18 papers: 19 decompositions in total, examined as their own part in 17 papers (June 2021 hides one inside a substitution). Fourteen are two distinct linear factors; the decomposition is almost never the end goal, because 17 of the 19 feed an integral, a differential equation or an expansion.

Session (question) Fraction Form Fed into
Jun 2026 (Q1a) (2 + 11x)/((1 + x)(2 + 5x)) = 3/(1 + x) − 4/(2 + 5x) Distinct Binomial expansion
Jan 2026 (Q4b) (2u − 5)/(u(u − 4)) = 5/(4u) + 3/(4(u − 4)) Distinct, in u Definite integral after u = ex + 4, giving P ln 2 + Q ln 3
Oct 2025 (Q9b) k/((t + 1)(2t + 5)) Distinct, in t Parametric area, answer ln α
Jun 2025 (Q4) (5 + 17x − 10x2)/(x(1 − x)(2x + 1)) = 5/x + 4/(1 − x) + 8/(2x + 1) Three distinct factors Definite integral, 5 ln 2 + 4 ln(3/5)
Jan 2025 (Q5ii) (2x + 11)/((2x + 1)(2 − x)) Distinct Definite integral, ln k
Oct 2024 (Q9a) 1/(x(2x − 1)) = 2/(2x − 1) − 1/x Distinct Differential equation (fairground ride)
Oct 2024 (Q7a) (3x − 1)/(x + 2) = 3 − 7/(x + 2) Improper, linear over linear Volume, π(p + q ln 2)
Jun 2024 (Q5c) (t + 1)/(t(3 − t)) = 1/(3t) + 4/(3(3 − t)) Distinct, in t Parametric area
Jan 2024 (Q2) (3x + 4)/((x − 2)(2x + 1)2) = 2/(5(x − 2)) − 4/(5(2x + 1)) − 1/(2x + 1)2 Repeated factor Definite integral, p ln q + r
Oct 2023 (Q7c) 3/(x(9 − 2x)) = 1/(3x) + 2/(3(9 − 2x)) Distinct Differential equation (goats)
Jun 2023 (Q3) (8x − 5)/((2x − 1)(4x − 3)) = 1/(2x − 1) + 2/(4x − 3) Distinct Integral, then solve for a limit k
Jan 2023 (Q1a) (5x + 10)/((1 − x)(2 + 3x)) = 3/(1 − x) + 4/(2 + 3x) Distinct Binomial expansion
Oct 2022 (Q2) 3x/((2x − 1)(x − 2)) = −1/(2x − 1) + 2/(x − 2) Distinct Definite integral, ln k
Jun 2022 (Q2a) 1/((1 + 3x)(1 − x)) = 3/(4(1 + 3x)) + 1/(4(1 − x)) Distinct Differential equation, sin4y = (1 + 3x)/(5(1 − x))
Jan 2022 (Q3b) 12/((7 − x)(1 + x)) Distinct Rewriting a Cartesian equation as a/(x + b) + c/(x + d)
Oct 2021 (Q3) (3x3 + 8x2 − 3x − 6)/(x(x + 3)) = 3x − 1 − 2/x + 2/(x + 3) Improper, cubic over quadratic Differentiate, then argue g′(x) > 3
Jun 2021 (Q4) 20/(u(5 + 2u)) = 4/u − 8/(5 + 2u) Distinct, in u Definite integral after u = √x, 4 ln(14/9)
Jan 2021 (Q10a) 1/((H − 5)(H + 3)) = (1/8)/(H − 5) − (1/8)/(H + 3) Distinct Differential equation (tank depth)
Oct 2020 (Q7ii) (6x2 − 16)/((x + 1)(2x − 3)) = 3 + 2/(x + 1) − 1/(2x − 3) Improper, quadratic over quadratic Indefinite integral
  • Forms: 14 two-factor distinct, 3 improper (Oct 2020, Oct 2021, Oct 2024), 1 repeated factor (Jan 2024), 1 with three distinct factors (Jun 2025). All three improper cases fell in October sessions.
  • What it fed: a definite or indefinite integral ending in logs 11 times, a differential equation 4, a binomial expansion 2, and once each a derivative argument and a Cartesian form.
  • In a new variable: four decompositions were in u or t (Jun 2021, Jun 2024, Oct 2025, Jan 2026), so students meet partial fractions mid-way through a substitution or a parametric area, not only as part (a).
  • The log step carries the marks: ∫1/(ax + b) dx = (1/a) ln|ax + b| and combining logs into the requested form (p ln q + r, ln k) are where the A marks sit.

Implicit differentiation

Implicit differentiation is in all 18 papers (8.4 marks on average, range 6–10). The product rule on an x-and-y term is needed in 17 of them, and since June 2022 the follow-up has moved from “tangent or normal at a point” towards “find the point where the gradient meets a condition” (7 of the last 13).

Session (question, marks) Curve Terms that need care Follow-up task
Jun 2026 (Q6, 10) 4xy2 + 12y + 6x = 53 Product Maximum value of x: denominator 4xy + 6 = 0, substitute back for a and b
Jan 2026 (Q7, 9) x2 tan y + 32y2/π2 = 11 Product with a trig function of y x at y = π/4; exact dy/dx at P; tangent gradient at P × normal gradient at Q
Oct 2025 (Q4, 10) 4x2 + y2 − 2xy = 24x Product Gradient 2 at P(a, b): gives y = 12 − 2x, substitute back
Jun 2025 (Q1, 8) 2y2 − 6xy = 7e^(2x−1) + 13 Product, e^(ax+b) Two y values at x = 1/2; tangent at the positive one, integer form
Jan 2025 (Q2, 8) 3x + 5y2 + 4x2y = 10(2^x) + 35 Product, a^x dy/dx (6 marks); exact gradient at P on the y-axis
Oct 2024 (Q4, 9) 3x2 + 2y2 − 4xy + 8^x − 11 = 0 Product, a^x Verify P(1, 2); normal meets the x-axis at a + b ln 2
Jun 2024 (Q3, 7) 8x3 − 3y2 + 2xy = 9 Product Normal at (2, 5), integer form
Jan 2024 (Q3, 9) y2x + 3y = 4x2 + k Product, unknown k P(p, 2) is a minimum turning point: find p and k
Oct 2023 (Q5, 10) y3 − x2 + 4x2y = k Product, unknown k Normal at P is y = x: gradient −1 at a point with y = x, so p = 2 and k = 36
Jun 2023 (Q2, 10) 2^x − 4xy + y2 = 13 Product, a^x y at x = 2; tangent meets the x-axis at (a ln 2 + b)/(c ln 2 + d)
Jan 2023 (Q5, 7) y2 = 2x2 + 15x + 10y None Curve not defined on (p, q): vertical tangents where y = 5
Oct 2022 (Q11, 9) (x + y)3 + 10y2 = 108x Chain rule on a bracket Show dy/dx; furthest point south (dy/dx = 0), to the nearest 100 m
Jun 2022 (Q4, 8) 16x3 − 9kx2y + 8y3 = 875 Product, unknown k Stationary point at x = 5/2: ky = 20/3, back into the curve, k = 4/3
Jan 2022 (Q1, 6) xy2 = x2y + 6 Product twice Tangent at (2, 3), integer form
Oct 2021 (Q1, 7) 2x − 4y2 + 3x2y = 4x2 + 8 Product Normal at (3, 2): 11x − 14y − 5 = 0
Jun 2021 (Q5, 9) y2 = ye^(−2x) − 3x Product, e^(kx) Show dy/dx; tangents at O and at P on the y-axis meet at R(1/8, 3/8)
Jan 2021 (Q6, 9) 4y2 + 3x = 6ye^(−2x) Product, e^(kx) dy/dx; normal at P on the y-axis as y = mx + c
Oct 2020 (Q6, 7) y = x^(sin x) Take logs first dy/dx; stationary points satisfy tan x + x ln x = 0
  • Follow-up tasks: a tangent or normal at a point 8 times (two of them then meet an axis); dy/dx = 0 four times (Oct 2020, Jun 2022, Oct 2022, Jan 2024); a vertical tangent twice (Jan 2023, Jun 2026); a given gradient twice (Oct 2023, Oct 2025); a gradient product once (Jan 2026).
  • The condition questions share one route: set the numerator, the denominator or the gradient expression to the condition, get a link between x and y, then substitute that link into the curve. The last step carries 2–3 marks and is the one weaker students skip.
  • a^x terms (2^x, 8^x) appear three times since June 2023, so d/dx(a^x) = a^x ln a from P3 is assumed, and answers come out in ln 2.
  • Exponentials of x (e^(−2x), e^(2x−1)) appear three times (Jan 2021, Jun 2021, Jun 2025), always multiplied by y or on the right-hand side.
  • Unknown constants in the curve (k) appear three times; each is found from the follow-up condition.
  • Points on the y-axis (Jan 2021, Jun 2021, Jan 2025) need x = 0 in the curve before any differentiation.

Parametric equations

Every paper has a parametric question, 25 in all (9.1 marks a paper, range 2–13). Trigonometric parametrisations dominated to October 2024 (10 of 18 curves). Since June 2025, four of the six curves have been rational, such as x = 4/(t + 2), and three of those converted to a rational Cartesian form.

Session (question, marks) x and y Type Tasks
Jun 2026 (Q3, 11) x = 4/(t + 2), y = 6t/(t + 4) Rational Tangent at t = 2; Cartesian f(x) = (12 − 6x)/(x + 2) on 0 < x < k; range of f
Jan 2026 (Q9, 8) x = 6 sin t, y = 5 sin 2t Trigonometric Volume, see Volumes and areas
Jan 2026 (Q5, 11) x = (4t − 5)/(2t + 1), y = 2t2 − 4t + 4, t ≥ 0 Rational and quadratic P(1, 10); dy/dx; tangent y = 28x − 18; domain −5 ≤ x < 2; range f(x) ≥ 2
Oct 2025 (Q9, 15) x = ln(2t + 5), y = 1/(t + 1) Logarithmic Point where the gradient is −4 (t = −1/4, y = 4/3); area for ln 9 ≤ x ≤ ln 15
Oct 2025 (Q3, 7) x = (t + 15)/(t + 4), y = 5/(t + 2) Rational Cartesian g(x) = (ax + b)/(cx + d) with its domain; range of g
Jun 2025 (Q5, 9) x = (3 + 2t)/(1 − t), y = 1 − t2 Rational and quadratic Normal at t = 2, through (−7, −3); Cartesian y = (10x − 5)/(x + 2)2
Jan 2025 (Q9, 12) x = 2 cos 2t, y = sin3t Trigonometric dy/dx = −(3/8) sin t; tangent 3x + 16y − 5 = 0; where it meets the curve again
Oct 2024 (Q10, 8) x = 3t2, y = sin t sin 2t Polynomial and trigonometric Area, see Volumes and areas
Oct 2024 (Q3, 9) x = 3 sin3θ, y = 1 + cos 2θ Trigonometric dy/dx = k cosec θ; tangent 16x + 18y − 33 = 0; Cartesian 8x2 = 9(2 − y)3
Jun 2024 (Q5, 13) x = t2 + 2t, y = 2/(t(3 − t)) Polynomial and rational Ends on y = 1 (t = 1, 2); area between the curve and y = 1
Jan 2024 (Q9, 12) x = sec t, y = √3 tan(t + π/3) Trigonometric, compound angle dy/dx; tangent y = 2x − 7; Cartesian via the compound-angle formula and sec2t = 1 + tan2t
Oct 2023 (Q8, 14) x = 6t − 3 sin 2t, y = 2 cos t Trigonometric k = 3π; dy/dx = −(1/6) cosec t; tangent meets the y-axis at N; volume
Jun 2023 (Q8, 12) x = t + 1/t, y = t − 1/t Rational Q(2, 0); P(2.5, 1.5); normal 3x + 5y = 15; volume
Jan 2023 (Q8, 11) x = sin2t, y = 2 tan t Trigonometric Normal at t = π/4: 2x + 8y = 17; area bounded by the curve, the normal and the x-axis
Jan 2023 (Q2, 6) x = (t − 1)/(2t + 1), y = 6/(2t + 1) Rational Show the points lie on a straight line (y = 2 − 4x); meet y = x + 12
Oct 2022 (Q6, 8) x = 1 + 3 tan t, y = 2 cos 2t Trigonometric Tangent where the curve crosses the x-axis; domain end k; range of f
Oct 2022 (Q1, 3) x = t/(t − 3), y = 1/t + 2 Rational Cartesian y = (7x − 1)/(3x)
Jun 2022 (Q7, 12) x = sin t − 3cos2t, y = 3 sin t + 2 cos t Trigonometric Gradient 3 at t = π; tangent y = 3x + 7; meets the curve again where 9cos2t + 2 cos t − 7 = 0
Jan 2022 (Q5, 10) x = √(9 − 4t), y = t3/√(9 + 4t) Roots Area, see Volumes and areas
Jan 2022 (Q3, 9) x = 3 + 2 sin t, y = 6/(7 + cos 2t) Trigonometric Cartesian y = 12/((7 − x)(1 + x)) on 1 ≤ x ≤ 5; then partial fractions
Oct 2021 (Q5, 9) x = 5 + 2 tan t, y = 8 sec2t Trigonometric Gradient −8 at x = 3; Cartesian y = 2(x − 5)2 + 8; range 8 ≤ f(x) ≤ 32
Jun 2021 (Q6, 10) x = 2 cos 2t, y = 4 sin t Trigonometric Area 8√2/3; Cartesian y = √(8 − 4x); range
Jan 2021 (Q9, 10) x = tan θ, y = 2 sin 2θ Trigonometric Volume, see Volumes and areas
Jan 2021 (Q4, 7) x = 1/t + 2, y = (1 − 2t)/(3 + t), t > 0 Rational Cartesian g(x) = (x − 4)/(3x − 5), x > 2; range of g
Oct 2020 (Q4, 12) x = 2t2 − 6t, y = t3 − 4t Polynomial Axis crossings; tangent at B: 7y + 4x − 80 = 0; meets the curve again at x = −40/49
  • Types: 12 trigonometric, 9 rational or rational-and-polynomial, one each polynomial, roots, logarithmic, and polynomial with trigonometric.
  • Cartesian conversions (11 curves): by identity when trigonometric (cos 2t = 1 − 2sin2t in Jun 2021, Jan 2022 and Oct 2024; sec2t = 1 + tan2t in Oct 2021 and Jan 2024; compound angle in Jan 2024), otherwise by making t the subject. Domain or range is asked 8 times, twice with no explicit conversion first (Oct 2022 Q6, Jan 2026 Q5).
  • Tangent meets the curve again (Oct 2020, Jun 2022, Jan 2025): substitute x(t), y(t) into the line. The contact point gives a repeated root, so (t − t0)2 is a factor; Jun 2022 turns the same idea into a quadratic in cos t.
  • Range traps: the extreme value can sit inside the interval, not at an end (t = 0 in Oct 2021; t = 1 in Jan 2026).
  • Parametric areas and volumes are set in 10 of these curves; they are analysed in Volumes and areas.

Connected rates of change

Connected rates appear in 13 of 18 papers (4.1 marks a paper, range 0–8). Spheres and balloons are the most common shape (5 times), and June 2026 Q4 re-ran June 2021 Q3 almost exactly, with a square root added to the volume formula.

Session (question, marks) Context Formula given or built Rate given Asked
Jun 2026 (Q4, 7) Container filling V = (1/3)h2√(h + 4), 0 ≤ h ≤ 21 (given) dV/dt = 30 Time to fill (24.5 s); exact dh/dt at h = 5 (108/41), product rule with a root
Jan 2026 (Q8a, 3) Balloon deflating V = (4/3)πr3 dV/dt constant Show dr/dt = −k/r2, which starts a differential equation
Jun 2025 (Q2, 4) Ice ball melting V = (4/3)πr3 (given) dV/dt = −k Show dr/dt is inversely proportional to r2
Jan 2025 (Q4i, 4) Balloon inflating V = (4/3)πr3 (given) dV/dt = 70π dr/dt at r = 5
Oct 2024 (Q5, 6) Inverted cone filling Similar triangles give V = 4πh3/75 (show) dV/dt = 2π dh/dt after 1.5 minutes: V = 180π, h = 15, dh/dt = 1/18
Jun 2024 (Q4, 6) Circle segment, radius 5 A = (25/2)(θ − sin θ), so dA/dθ = K(1 − cos θ) dθ/dt = 0.1 dA/dt at a given θ
Jan 2024 (Q4, 5) Cone, height fixed at 5 l = √(25 + r2); S = πr2 + πrl (given) dr/dt = 3 dS/dt at r = 1.5, to 1 d.p.
Oct 2023 (Q2, 7) Expanding cube S = 6x2, V = x3 dS/dt = 4 Show dx/dt = 1/(3x); show dV/dt = V^(1/3)
Jan 2023 (Q7a, d; 4) Balloon V = (4/3)πr3 (given) From the solved differential equation dV/dr; dr/dt at t = 3, with units
Jun 2022 (Q3, 8) Circle, then cylinder A = πx2, V = 3πx3 dA/dt = −0.5 dx/dt at x = 7 (−1/(28π)); dV/dt at x = 4 (−9)
Jan 2022 (Q4, 8) Icosahedron A = 5√3x2 (show); V given dA/dt = 0.025 Show dV/dA; dV/dt at x = 2, to 2 s.f.
Oct 2021 (Q9a, 4) Cylindrical tank, diameter 8 m V = 16πh; in 0.6π, out 0.15πh Net dV/dt Show dh/dt = (12 − 3h)/320, which is then solved
Jun 2021 (Q3, 7) Bowl filling V = (1/3)h2(h + 4), 0 ≤ h ≤ 20 (given) dV/dt = 160 Time to fill (20 s); dh/dt at h = 5 (96/23)
  • Missing in October 2020, January 2021, October 2022, June 2023 and October 2025. No paper has gone two sessions in a row without one since 2021.
  • Shapes: spheres and balloons 5, cones 2, cylinders and circles 2, containers with a given V(h) 2, a cube, an icosahedron and a circle segment once each.
  • Formula given vs built: the question supplies the volume or area formula in 7 of the 13. Students build it themselves for the cube, the cylinder pieces, the segment area, the cone (similar triangles) and, in January 2026, the sphere, whose formula was not printed.
  • Three rates questions start a differential equation (Oct 2021, Jan 2023, Jan 2026): the chain rule produces dh/dt or dr/dt, which the next part separates and solves.
  • Calculus beyond the chain rule: the June 2026 volume needs the product rule on h2√(h + 4); the January 2024 surface area needs the chain rule on √(25 + r2).

Integration by substitution

A substitution integral appears in all 18 papers (6.2 marks a paper, range 3–8), 18 in total. The substitution is printed in 16 of them; only October 2020 and October 2023 left the choice to the student. The real test is usually what comes after the change of variable: partial fractions, parts, a trig identity or a reverse chain rule.

Session (question, marks) Integral Substitution Type What the u-integral became
Jun 2026 (Q7ii, 7) ∫2x3/√(1 − 4x2) dx, definite 2x = sin u Trig substitution (1/8)∫sin3u du, using sin3u = sin u(1 − cos2u)
Jan 2026 (Q4, 9) ∫ from 0 to ln 6 of (2ex + 3)/(ex + 4) dx u = ex + 4 Exponential (2u − 5)/(u(u − 4)) on [5, 10]; partial fractions, P ln 2 + Q ln 3
Oct 2025 (Q6, 7) ∫sin 2θ/√(3 + cos θ) dθ, definite u = 3 + cos θ Trig inside −2(u − 3)/√u on [3, 4]; powers of u, a√3 + b
Jun 2025 (Q7, 6) ∫(tan x + tan3x)/(4 + sec2x)3 dx, indefinite u = tan x Trig inside u/(5 + u2)3; reverse chain rule
Jan 2025 (Q7, 6) ∫1/(16 − x2)^(3/2) dx, definite x = 4 sin θ Trig substitution (1/16)∫sec2θ dθ
Oct 2024 (Q6, 5) ∫9x5/√(x3 + 1) dx, indefinite u = √(x3 + 1) Root 6∫(u2 − 1) du
Jun 2024 (Q9, 9) Volume π∫x^(−1/2)/((1 + x)(arctan √x)2) dx on [1, 3] tan u = √x Inverse-trig substitution 2π∫u−2 du on [π/4, π/3], V = 2
Jan 2024 (Q7, 8) ∫e^(4x + 2 sin 2x) cos2x dx, then a volume u = 4x + 2 sin 2x Trig inside (1/8)∫eu du, since du/dx = 8cos2x
Oct 2023 (Q3ii, 7) ∫4x/(2x − 1)2 dx, definite Not given (u = 2x − 1 accepted) Linear (u + 1)/u2, giving ln u − 1/u; a + ln b
Jun 2023 (Q5ii, 6) ∫27x/√(1 − 3x) dx, indefinite u = √(1 − 3x) Root −6∫(1 − u2) du; −2(Ax + B)√(1 − 3x) + k
Jan 2023 (Q4, 9) ∫(8x + 4)…e^√(2x + 1) dx, definite u = √(2x + 1) Root ∫ from 3 to 5 of 2u2eu du; parts twice, 34e5 − 10e3
Oct 2022 (Q7i, 7) ∫ from ln 5 to ln 7 of 4e3x/(ex − 3) dx u = ex − 3 Exponential 4(u + 3)2/u; divide, then 2u2 + 24u + 36 ln u; a + b ln 2
Jun 2022 (Q5, 8) ∫ from 0 to 1 of (3x + 2)/(4 − x2)^(3/2) dx x = 2 sin u Trig substitution (3/2)sec u tan u + (1/2)sec2u; 7√3/6 − 3/2
Jan 2022 (Q5b, 6) Parametric area ∫t3/√(81 − 16t2) dt u = 81 − 16t2 (or otherwise) Polynomial inside a root Powers of u
Oct 2021 (Q6, 7) Area ∫16 sin 2x/(3 + 4 sin x)2 dx on [π/6, π/2] u = 3 + 4 sin x Trig inside 2/u − 6/u2 on [5, 7]; ln(49/25) − 12/35
Jun 2021 (Q4, 8) ∫ from 1 to 4 of 10/(5x + 2x√x) dx u = √x Root 20/(u(5 + 2u)); partial fractions, 4 ln(14/9)
Jan 2021 (Q5, 8) ∫4/(3 + √(2x − 1)) dx, definite u = 3 + √(2x − 1) Root 4(u − 3)/u; divide, p + q ln 2
Oct 2020 (Q7i, 6) ∫ from 1 to 5 of 3x/√(2x − 1) dx Not given (u = √(2x − 1) or u = 2x − 1) Root Powers of u; 16
  • Substitution types: roots 6, trig functions inside (u = 3 + 4 sin x and similar) 4, trig substitutions (x = a sin θ, tan u = √x) 4, exponential 2, linear or polynomial 2.
  • What follows the change of variable: powers of u 8 times, partial fractions 2, division of a fraction 2, parts 1, trig integrals 3, eu once, a reverse chain rule once.
  • Definite 15, indefinite 3 (Jun 2023, Oct 2024, Jun 2025). In definite ones the limits must be changed: the mark schemes award an M mark for using the u-limits, and returning to x is never needed.
  • Context: 14 standalone, 2 areas (Oct 2021; Jan 2022, parametric), 2 volumes (Jan 2024, Jun 2024).
  • Trig substitutions are rising: x = 2 sin u (Jun 2022), x = 4 sin θ (Jan 2025), 2x = sin u (Jun 2026). Each relies on 1 − sin2θ = cos2θ to clear a root.
  • The step the schemes police hardest: converting dx. The June 2021 scheme states that dx cannot simply be replaced by du; doing so loses the method mark for changing the integral.

Integration by parts

Integration by parts appears in every paper: as its own part in 16, and inside a differential equation in the other two (June 2021, October 2025). LIATE gives a correct choice of u in all 19 integrals: u = a logarithm 4 times, u = a power of x 11 times, and the 4 ex-times-trig loops work with either choice.

Session (question, marks) Integral u (LIATE letter) dv/dx Applications Context and result
Jun 2026 (Q7i, 6) ∫e^(2x) cos 4x dx Either; scheme Way One uses u = e^(2x) cos 4x Loop Standalone; (1/5)e^(2x) sin 4x + (1/10)e^(2x) cos 4x + c
Jan 2026 (Q2, 5) ∫ from 2 to 2e2 of x3 ln(x/2) dx ln(x/2), L x3 Once Standalone, exact value
Oct 2025 (Q8a, 5) ∫12t e^(−t) dt 12t, A e^(−t) Once Differential equation: V = 18 − 12te^(−t) − 12e^(−t)
Jun 2025 (Q9b, 4) ∫ex cos x dx Either; scheme shows both ways cos x or ex Loop Volume of a paperweight
Jan 2025 (Q5i, 4) ∫x2e^(4x) dx x2, A e^(4x) Twice Standalone; (1/4)x2e^(4x) − (1/8)xe^(4x) + (1/32)e^(4x) + c
Oct 2024 (Q10b, 5) ∫12t sin2t cos t dt t, A sin2t cos t, so v = (1/3)sin3t Once, then ∫sin3t by identity Parametric area, pπ + q
Jun 2024 (Q1, 5) ∫ from 0 to π/6 of x cos 3x dx x, A cos 3x Once Standalone; π/18 − 1/9
Jan 2024 (Q5a, 4) ∫x2 cos 2x dx x2, A cos 2x Twice Then used to solve a differential equation
Oct 2023 (Q3i, 5) ∫x2e^(2x) dx, exact value x2, A e^(2x) Twice Standalone
Jun 2023 (Q5i, 4) ∫x2ex dx x2, A ex Twice Standalone; x2ex − 2xex + 2ex + c
Jan 2023 (Q4b, 5) ∫ from 3 to 5 of 2u2eu du u2, A eu Twice After the substitution u = √(2x + 1); 34e5 − 10e3
Oct 2022 (Q7ii, 5) ∫3ex cos 2x dx Either; main scheme uses u = 3ex cos 2x Loop Standalone show-that; (6/5)ex sin 2x + (3/5)ex cos 2x + c
Jun 2022 (Q8b, 3) ∫x2e^(−x) dx x2, A e^(−x) Twice Volume, then density
Jan 2022 (Q7b, 5) ∫ from 0 to 4 of (x2 − 8x + 16)e^(2x) dx The quadratic, A e^(2x) Twice Volume of a doorknob
Oct 2021 (Q8b, 4) ∫ from 1 to e of x2(ln x)2 dx (ln x)2, L x2 Once, reusing (a) Volume; π(5e3 − 2)/27
Oct 2021 (Q8a, 3) ∫x2 ln x dx ln x, L x2 Once Feeds (b); (x3/3) ln x − x3/9 + c
Jun 2021 (Q8a, part) ∫6xe^(−2x) dx 6x, A e^(−2x) Once Differential equation; y^(2/3) = 2 − (2x + 1)e^(−2x)
Jan 2021 (Q7a, 5) ∫e^(2x) sin x dx sin x, T (scheme Way 1) e^(2x) Loop Then an area; (e^(2π) + 1)/5
Oct 2020 (Q5a, 3) ∫ln x/x2 dx ln x, L x^(−2) Once Then an area; 1 + 2 ln 2
  • LIATE counts: L (logarithm) 4, A (algebraic) 11, loops 4. I (inverse trig) never appears as u. Every choice that LIATE makes is one the mark schemes accept.
  • The loop is the one place to choose freely. LIATE says u = trig (T before E); Jan 2021’s scheme does that, Oct 2022’s and Jun 2026’s main methods take u = e^(ax), and Jun 2025’s shows both. What matters is keeping the same choice for the second application; swapping it undoes the first step.
  • Applications: once 8, twice 7, loop 4. Every “twice” case is x2 times an exponential or a cosine (or the quadratic in Jan 2022).
  • Exponents and arguments seen: ex, e^(2x), e^(4x), e^(−x), e^(−2x), e^(−t); cos 2x, cos 3x, cos 4x, sin x, cos x; ln x, (ln x)2, ln(x/2). The linear coefficient is the main source of slips (v = (1/4)e^(4x), not e^(4x)).
  • Context: 7 standalone, 5 inside volumes (4 papers), 3 inside areas, 3 inside differential equations, 1 after a substitution. Integration by parts is the main tool for finishing volume questions.
  • ∫ln x dx on its own (u = ln x, dv/dx = 1) has not been set in this period.
  • Marking points: M1 for parts “the right way round” to the correct form, dM1 for the second application, A1 for the result, with +c usually required on indefinite answers. The June 2022 scheme explicitly credits the tabular (DI) method, row by row.

Volumes and areas

A volume of revolution appeared in 17 of the 18 papers; June 2026 is the only paper with no volume or area at all. Most volumes are really integration-technique questions in disguise: setting up π∫y2 dx is worth 1–3 marks, and finishing the integral (parts, substitution, partial fractions, a trig identity) carries the rest.

Session (question, marks) Curve Region Volume or area How the integral is finished Result
Jun 2026 None
Jan 2026 (Q9, 8) x = 6 sin t, y = 5 sin 2t, 0 ≤ t ≤ π/2 Curve and x-axis Parametric volume 600π∫sin2t cos3t dt; cos3t = cos t(1 − sin2t), reverse chain rule 80π
Oct 2025 (Q9b, 9) x = ln(2t + 5), y = 1/(t + 1) ln 9 ≤ x ≤ ln 15 Parametric area ∫ from 2 to 5 of 2/((t + 1)(2t + 5)) dt; partial fractions ln α
Oct 2025 (Q2, 5) Cartesian curve 2 ≤ x ≤ 8 Volume Algebraic integration, exact Exact
Jun 2025 (Q9, 12) y = cos x + ex/5 Curve, axes and a vertical line Volume, then a paperweight made of two solids Expand y2; cos2x by identity; ∫ex cos x by the parts loop 2 s.f.
Jan 2025 (Q1, 5) y = 4/(x + 2) 0 ≤ x ≤ 8 Volume 16π∫(x + 2)−2 dx 32π/5
Oct 2024 (Q10, 8) x = 3t2, y = sin t sin 2t, 0 ≤ t ≤ π Curve and x-axis Parametric area 12∫t sin2t cos t dt; parts pπ + q
Oct 2024 (Q7b, 6) y = √((3x − 1)/(x + 2)) 1 ≤ x ≤ 4 Volume Divide: 3 − 7/(x + 2), then a log π(p + q ln 2)
Jun 2024 (Q9, 9) y2 = x^(−1/2)/((1 + x)(arctan √x)2) 1 ≤ x ≤ 3 Volume tan u = √x gives 2π∫u−2 du 2
Jun 2024 (Q5b–c, 11) x = t2 + 2t, y = 2/(t(3 − t)) Curve and the line y = 1 Parametric area 4∫(t + 1)/(t(3 − t)) dt with a rectangle; partial fractions Exact
Jan 2024 (Q7, 8) An e^(2x + sin 2x) cos x curve Curve and both axes Volume Substitution u = 4x + 2 sin 2x from part (a) Exact
Oct 2023 (Q8d, 6) x = 6t − 3 sin 2t, y = 2 cos t Curve and both axes Parametric volume 48π∫sin2t cos2t dt = 6π∫(1 − cos 4t) dt Exact
Jun 2023 (Q8d, 7) x = t + 1/t, y = t − 1/t Curve, the normal at P and the x-axis Parametric volume plus a cone π∫y2(dx/dt) dt, then add a cone Exact
Jan 2023 (Q8b, 6) x = sin2t, y = 2 tan t Curve, the normal and the x-axis Parametric area plus a triangle ∫4 sin2t dt by identity, then a triangle Exact
Jan 2023 (Q3, 5) y2 = 3x/(3x2 + 5) Between two vertical lines Volume f′(x)/f(x), giving a log a ln b, a irrational, b prime
Oct 2022 (Q5, 6) y = 12√x/(2x2 + 3)^1.5 1 ≤ x ≤ k Volume given as 713π/648 Reverse chain rule: −18(2x2 + 3)−2 Solve for k
Jun 2022 (Q8, 10) y = 10xe^(−x/2) 0 ≤ x ≤ 10, doubled Volume, then density = mass ÷ volume 100π∫x2e^(−x) dx; parts twice 3.99 g/cm3
Jan 2022 (Q7, 8) f(x) = (1/4)(4 − x)ex 0 ≤ x ≤ 4 Volume of a doorknob (π/16)∫(x2 − 8x + 16)e^(2x) dx; parts twice pπ(e^q + r)
Jan 2022 (Q5, 10) x = √(9 − 4t), y = t3/√(9 + 4t) Curve and both axes Parametric area 2∫t3/√(81 − 16t2) dt; substitution u = 81 − 16t2 Exact
Oct 2021 (Q8b, 4) y = x ln x 1 ≤ x ≤ e Volume Parts on x2(ln x)2, reusing (a) π(5e3 − 2)/27
Oct 2021 (Q6, 7) y = 16 sin 2x/(3 + 4 sin x)2 π/6 ≤ x ≤ π/2 Area Substitution u = 3 + 4 sin x ln(49/25) − 12/35
Jun 2021 (Q6a, 6) x = 2 cos 2t, y = 4 sin t Curve and both axes Parametric area 32∫sin2t cos t dt; reverse chain rule 8√2/3
Jun 2021 (Q2, 7) y = 9/(2x − 3)^1.25 Curve, y = 9 and x = 6 Volume: cylinder minus curve Power rule on (2x − 3)^(−2.5) 298π
Jan 2021 (Q9, 10) x = tan θ, y = 2 sin 2θ 0 ≤ x ≤ √3 Parametric volume 8π∫(1 − cos 2θ) dθ 8π2/3 − 2√3π
Jan 2021 (Q7b, 2) y = e^(2x) sin x 0 ≤ x ≤ π Area From the parts loop in (a) (e^(2π) + 1)/5
Oct 2020 (Q5b, 4) y = (3 + 2x − ln x)/x2 2 ≤ x ≤ 4 Area Parts result from (a) 1 + 2 ln 2
Oct 2020 (Q3, 6) y = e^(0.5x) − 2 Curve and both axes Volume Expand y2 8π ln 2 − 5π
  • Volumes: 13 Cartesian and 4 parametric (Jan 2021, Jun 2023, Oct 2023, Jan 2026). Areas: 6 parametric and 3 Cartesian.
  • Finishing technique for the 17 volumes: parts in 4 (Oct 2021, Jan 2022, Jun 2022, Jun 2025), a trig identity in 3, the reverse chain rule in 2, the power rule in 2, a substitution in 2, and once each a log by division, f′/f, plain expansion and a parametric power integral. October 2025’s is a plain algebraic integral.
  • Composite regions (curve plus a cylinder, cone, triangle or rectangle) in Jun 2021, Jan 2023, Jun 2023 and Jun 2024.
  • Real objects (Jan 2022 doorknob, Jun 2022 density, Jun 2025 paperweight) add a final step that uses the volume, worth 1–4 marks.
  • Working backwards from a given volume to a limit happened once (Oct 2022).
  • Parametric volumes always reduce to a product of sin and cos powers, cleared by a double-angle identity or by writing an odd power as one factor times (1 − sin2) or (1 − cos2).

Differential equations

Every paper has a separable differential equation: 19 in all (October 2021 has two), worth 8.4 marks a paper on average (range 5–12). 13 of the 19 are set in context, and since January 2024 the integration on one side has often needed a P4 technique: partial fractions, parts or a trig result.

Session (question, marks) Equation and condition Integration needed Context Asked after solving
Jun 2026 (Q8, 10) dS/dt = (128 − S)/50, S = 18 at t = 0 (after a non-DE first model) ∫dS/(128 − S), a log Algae on a pond S = 128 − 110e^(−t/50); maximum area 128 m2
Jan 2026 (Q8, 10) dr/dt = −k/r2, built from a constant rate of volume loss ∫r2 dr Deflating balloon r(t) from r = 30 at t = 0 and r = 12 at t = 24; time until V = 0, to 1 d.p.
Oct 2025 (Q8, 6) dV/dt = 12te^(−t), V = 6 at t = 0 Parts on the t side Water container V = 18 − 12te^(−t) − 12e^(−t); never full, since V → 18 < 20
Jun 2025 (Q3, 6) dy/dx = 3 sin 2x/(y cos22x), y = 4 at x = π/6 ∫3 sec 2x tan 2x dx None y2 = 3 sec 2x + 10
Jan 2025 (Q4ii, 6) dh/dt = k/h3, h = 4 at t = 0 and 6 at t = 5 ∫h3 dh Water depth in a cave k = 52; T when h = 10, to 1 d.p.
Oct 2024 (Q9, 10) dh/dt proportional to h(2h − 1) cos(t/10), h = 2.5 at t = 0 Partial fractions on the h side Fairground ride h in a given exponential form; time of the third maximum, nearest second
Jun 2024 (Q7, 11) dx/dt = k − 3x, x = 0 at t = 0 ∫dx/(k − 3x), a log Current in a circuit Long-term 7 A gives k = 21; time to reach 5 A, 2 s.f.
Jan 2024 (Q5b, 5) dy/dt = t2cos2t/y2 ∫t2cos2t dt via cos2t = (1 + cos 2t)/2 and part (a) None y3 = f(t)
Oct 2023 (Q7, 12) dx/dt = x(9 − 2x)/3, x = 3 at t = 0 (after a non-DE first model) Partial fractions Goats on an island x = 9/(2 + e^(−3t)); long-term populations from both models
Jun 2023 (Q6, 9) dθ/dt = −k(θ − 15), θ = 85 at t = 0 and 40 at t = 10 ∫dθ/(θ − 15), a log Engine cooling θ as an exponential; time to reach 20 °C, nearest minute
Jan 2023 (Q7b–c, 8) dV/dt = 900/(2t + 3)2, V = 0 at t = 0 Direct, a power of (2t + 3) Balloon V = 300t/(2t + 3); upper limit 150; radius at t = 3
Oct 2022 (Q10, 8) dr/dt = −k/r2, from “inversely proportional to the square of the radius” ∫r2 dr Melting ice ball r = 12 to 6 in 15 minutes; time to melt; sketch r against t
Jun 2022 (Q2b, 6) cot y dy/dx = 1/((1 + 3x)(1 − x)), y = π/2 at x = 1/2 ∫cot y dy = ln sin y; partial fractions on the x side None sin4y = (1 + 3x)/(5(1 − x))
Jan 2022 (Q9b–c, 9) 3 cosec 2x · dy/dx = y(1 + 2 ln y)3 ∫dy/(y(1 + 2 ln y)3), signposted by part (a)’s derivative None General, then particular solution in exponential form
Oct 2021 (Q9b, 6) dh/dt = (12 − 3h)/320, h = 0.5 at t = 0 ∫dh/(12 − 3h), a log Cylindrical tank Time to reach 3.5 m: (320/3) ln 7 ≈ 208 minutes
Oct 2021 (Q2, 6) dy/dx = 4y2/√(4x + 5), y = 1/3 at x = −1/4 ∫y−2 dy and ∫4(4x + 5)^(−1/2) dx None y = 1/(7 − 2√(4x + 5))
Jun 2021 (Q8, 9) dy/dx = 6xe^(−2x) y^(1/3), y = 1 at x = 0 Parts on the x side None y^(2/3) = 2 − (2x + 1)e^(−2x); horizontal asymptote y = 2√2
Jan 2021 (Q10b–d, 11) dH/dt = −(H − 5)(H + 3)/40, H = 13 at t = 0 Partial fractions Storage tank H = (10 + 3e^(−0.2t))/(2 − e^(−0.2t)); time to 8 m; long-term depth 5 m
Oct 2020 (Q9, 9) dA/dt = A^(3/2)/(5t2), A = 2.25 at t = 3 Powers Bacteria on a dish A = (30t/(19t + 3))2; limiting area 900/361 ≈ 2.49 cm2
  • Integration on the variable side: a log of a linear expression 4 times, powers 8, partial fractions 3, cot y once, a signposted composite once, and 2 direct integrations (Jan 2023, Oct 2025). On the independent side: parts 3 (Jun 2021, Jan 2024, Oct 2025), partial fractions once (Jun 2022), trig 3 (Jun 2025, Jan 2024, Oct 2024).
  • Context vs pure: 13 in context, 6 pure (Jun 2021, Oct 2021 Q2, Jan 2022, Jun 2022, Jan 2024, Jun 2025).
  • Built from words three times: “inversely proportional to r2” (Oct 2022), rates in and out of a tank (Oct 2021), a constant rate of volume loss (Jan 2026).
  • Follow-ups: a long-term or limiting value 8 times; a time 8 times; one sketch (Oct 2022). Two papers (Oct 2023, Jun 2026) open with a non-DE model to compare against.
  • Where marks are lost (from the scheme notes): one constant of integration, found from the starting values before rearranging; logs combined before exponentiating; and the final “in context” answer with units and the stated accuracy.

Vectors

Vectors are the largest topic: every paper, 10.7 marks on average (range 8–16), across 24 questions. Almost every part is one of five routines: where two lines meet, an angle by the scalar product, the foot of a perpendicular, an area, or a reflection. Six papers split vectors over two questions.

Session (question, marks) Set-up Tasks
Jun 2026 (Q5, 9) Triangle ABC from AB and AC Angle BAC (1 d.p.); area of ABC (1 d.p.); D on AB extended with angle ADC = 90°
Jun 2026 (Q2, 6) Two lines Explain why they are not parallel; prove by contradiction that they do not meet
Jan 2026 (Q6, 10) l1, and l2 with an unknown a Point P on l1 nearest O; a so the lines meet; their intersection Q
Oct 2025 (Q7, 6) Parallelogram from AB and BC Exact cos θ; area in the form 5√k
Oct 2025 (Q5, 6) l1, and l2 with an unknown β β so the lines meet; the intersection P
Jun 2025 (Q6, 8) A, B and C(3, α, 5) Line AB; exact values of α for which angle BAC = 45° (a quadratic)
Jan 2025 (Q8, 12) Line l; A(−2, a, 4) and B(b, 3, 1) on it; C a and b; AB; angle CAB (1 d.p.); both positions of D on l with area CAD = 2 × area CAB
Oct 2024 (Q8, 10) A and B; l2 with unknowns p, q Line AB; p and q so the lines meet at B; exact cos θ; exact length AC with AC ⊥ l2
Jun 2024 (Q6, 10) l1 and a point A with |OA| = 5√10 Show 81λ2 + 52λ − 220 = 0; both positions of A; area of OAB (1 d.p.) using l2 through O
Jun 2024 (Q2, 6) OA, AB, and OC with an unknown a Coordinates of B; values of a with OC ⊥ BC
Jan 2024 (Q6, 14) l1 with an unknown p, and l2 p so they meet; the intersection; acute angle (1 d.p.); B on l2 with AB ⊥ l2
Oct 2023 (Q6, 10) l1 and l2 meeting at P P; cos θ as a fraction; area of isosceles triangle QPR; both positions of R
Jun 2023 (Q4, 10) A, B and P Line AB; C on l with PC ⊥ l; reflection P′; |PP′| = 4√17
Jan 2023 (Q6, 8) A, B and C AB and line l; P on l with CP ⊥ l
Oct 2022 (Q9, 5) Two lines Prove they are skew
Oct 2022 (Q3, 5) Triangle PQR from PQ and PR RQ; angle PQR (3 s.f.)
Jun 2022 (Q6, 9) A, B, and C with an unknown p Line AB; AC ⊥ AB gives p = −8; area of ABC = 9√10
Jan 2022 (Q8, 11) A and B; l2; C on l2 Line AB; show the lines do not meet; acute angle between AC and l2 (1 d.p.)
Oct 2021 (Q7, 9) Line l and point A Foot X; shortest distance √67; reflection B of A in l
Jun 2021 (Q9i, 3) A, B, C collinear with AB : AC = 1 : 3 Show c = 3b − 2a
Jun 2021 (Q7, 10) Line l Unit vector OA parallel to l; point X on l closest to O, (7, −4, −6); area of OXA = √101/2
Jan 2021 (Q8, 6) Two lines with an unknown b Prove they are skew for every b ≠ 7
Jan 2021 (Q2, 5) Parallelogram from AB and BC Angle ABC (2 d.p.); area (1 d.p.)
Oct 2020 (Q8, 10) l1 and l2 Intersection X, −8i + 5j + 6k; Q on l2 with PQ ⊥ l2, (10/7, 2/7, −57/7)
  • Routine counts: an angle by the scalar product 10 times; the foot of a perpendicular (nearest point, shortest distance) 9; an area of a triangle or parallelogram 8; lines meeting, including finding a constant so they do, 6; proving lines skew or non-intersecting 4; a reflection 2.
  • Unknown constants in a line or point (a, b, p, q, α, β) appear in 9 questions. Each is found from one condition: the lines meet, two vectors are perpendicular, or an angle is given.
  • Two-answer parts (both positions of a point, or two values of a constant) appear 5 times, all since October 2023 (Oct 2023, Jun 2024 twice, Jan 2025, Jun 2025). They come from a quadratic in λ or from a ratio either side of a point.
  • Accuracy demands are shifting to exact forms: exact cos θ in Oct 2023, Oct 2024 and Oct 2025, and exact surd lengths or areas in Jun 2022, Jun 2023, Oct 2024 and Oct 2025. Degrees to 1 d.p. remain common.
  • Notation is marked: the October 2020 scheme rejects coordinates where a position vector is asked for, and penalises the wrong notation once.
  • Proof meets vectors in June 2026 Q2, where “the lines do not intersect” had to be written as a proof by contradiction.

Proof by contradiction

Proof by contradiction is in every paper (4.6 marks on average, range 2–8). Five families account for all 18; until mid-2023 they were almost all number theory, but since October 2023 five of nine have been tied to another topic: calculus, curves, trigonometry or vectors.

Session (question, marks) Statement Family The step that produces the contradiction
Jun 2026 (Q2b, 5) Two given 3D lines do not intersect Never meets Solve two components for λ and μ; the third component fails
Jan 2026 (Q3, 5) No positive integers satisfy x2 − 4y2 = 27 (after factorising) No integer solutions (x − 2y)(x + 2y) = 27; the pairs 1 × 27 and 3 × 9 give y = 6.5 and 1.5
Oct 2025 (Q10, 6) Complete: if x2 is odd, x is odd. Then: no integers with a2 − 4b = 27 Parity a is odd, a = 2m + 1, so 4(m2 + m − b) = 26, impossible
Jun 2025 (Q10, 4) cos 2x/(cos x − sin x) < 1 for 90° < x < 180° Inequality Leads to sin 2x ≥ 0, false for 180° < 2x < 360°
Jan 2025 (Q6, 4) If n2 − 4n + 5 is even, then n is odd Parity n = 2m makes n2 − 4n + 5 odd
Oct 2024 (Q2, 4) y = x4 + 10x2 + 8 and y = 2x2 − 7 do not meet Never meets x4 + 8x2 + 15 = 0 gives x2 = −3 or −5
Jun 2024 (Q8b, 4) A line and a curve from the binomial expansion in (a) do not meet Never meets The difference is 8(x − 1)2 + x3/24 > 0 on the interval
Jan 2024 (Q8, 4) y = 2x + x3 + cos x has no stationary points Never meets (no real solution) 3x2 + 2 − sin x = 0 is impossible, since 3x2 ≥ 0 and 2 − sin x ≥ 1
Oct 2023 (Q4, 5) k + 9/k ≥ 6 for all positive k; not true for all real k Inequality (k − 3)2 < 0 is impossible; a negative k is the counter-example
Jun 2023 (Q7, 4) √7 is irrational (lemma on multiples of 7 given) Irrational root p2 = 7q2 forces a common factor 7
Jan 2023 (Q9, 8) Complete: if p3 is a multiple of 3, so is p. Then: ∛3 is irrational Irrational root Both cases 3k + 1 and 3k + 2; then p3 = 3q3
Oct 2022 (Q8, 4) No positive integers satisfy 3x2 + 2xy − y2 = 25 (started for the student) No integer solutions (3x − y)(x + y) = 25; the pairs 5 × 5 and 25 × 1 fail
Jun 2022 (Q9, 4) n2 − 2 is never divisible by 4 Parity and divisibility n2 = 4k + 2 makes n even, then n2 − 2 = 2(2m2 − 1)
Jan 2022 (Q6, 5) k, 1 + 2k, 3 + 3k is not a geometric sequence Never meets (no real solution) (1 + 2k)2 = k(3 + 3k) gives k2 + k + 1 = 0, discriminant −3
Oct 2021 (Q10, 6) Complete: if n3 is even, n is even. Then: ∛2 is irrational Irrational root p3 = 2q3 makes p and q both even
Jun 2021 (Q9ii, 5) If n2 is a multiple of 3, so is n Divisibility n = 3p + 1 and n = 3p + 2, both cases
Jan 2021 (Q3, 2) There is no greatest odd integer Parity If N is the greatest, N + 2 is odd and greater
Oct 2020 (Q1, 4) If n3 is even, n is even Parity (2p + 1)3 = 2(4p3 + 6p2 + 3p) + 1 is odd
  • Families: parity and divisibility 6, never meets or no real solution 5, irrational roots 3, no integer solutions 2, inequalities 2. Families repeat in runs of up to three (parity from Oct 2020 to Jun 2021; never-meets from Jan 2024 to Oct 2024), so there is no reliable rotation.
  • The assumption line is a mark on its own (B1) in every scheme checked. It must negate the statement precisely: “there exists n such that n3 is even and n is odd”, not “for all n”.
  • Scaffolded “complete the proof” questions appear 4 times (Oct 2021, Oct 2022, Jan 2023, Oct 2025). Three of them pair a lemma with an application in the second part.
  • Cross-topic proofs since October 2023: a derivative (Jan 2024), a binomial expansion (Jun 2024), two curves (Oct 2024), trigonometry (Jun 2025) and vectors (Jun 2026).
  • Two-case arguments (3k + 1 and 3k + 2) are required in Jun 2021 and Jan 2023; missing a case caps the marks.

October 2026 predictions

The single strongest prediction is a volume of revolution: it appeared in 17 consecutive papers before June 2026 had none. These are patterns, not leaks; Pearson does not rotate P4 topics on a fixed cycle, and every paper covers almost the whole specification.

Rank Prediction Evidence from the 18 papers Confidence
1 A volume of revolution, finished by parts, a substitution, partial fractions or a trig identity; about a 1 in 4 chance it is parametric 17 of 18 papers; June 2026 was the first without one; 4 of the 17 were parametric Very high
2 Implicit differentiation followed by a gradient condition (stationary point, vertical tangent or given gradient), then substitution back into the curve; possibly an a^x term Every paper; the condition form in 7 of the last 13; a^x three times since June 2023 Very high (topic), high (condition form)
3 A parametric curve: dy/dx, a tangent or normal, then a Cartesian form with domain or range, most likely a rational parametrisation Every paper; tangent or normal in 12 of 18; Cartesian in 11; rational in 4 of the 6 curves since June 2025 Very high (topic), moderate (rational)
4 Binomial expansion as Question 1, with a bracket not starting with 1 and a validity range Question 1 in 11 of 18; a ≠ 1 in 11 of the last 13; validity in 4 of the last 5; October 2023 and October 2025 nearly identical Very high
5 Vectors worth 8–16 marks: an unknown constant so lines meet, an angle (possibly exact cos θ), the foot of a perpendicular and an area, perhaps with a two-answer part Every paper; the five routines cover almost every part; exact cos θ in all three Octobers since 2023 Very high
6 A differential equation in context: separate, integrate (log, partial fractions or parts), find c, then a time or a long-term value Every paper; 13 of 19 in context; a long-term value 8 times and a time 8 times Very high
7 A substitution integral with the substitution printed, definite, with the limits to change; a trig substitution is possible Every paper; printed in 16 of 18; x = a sin θ twice in the last 5 papers Very high (topic), moderate (trig form)
8 Integration by parts on x2 times an exponential or cosine (twice), or with u = ln x Every paper; x2 twice-through 7 times; u = ln x 4 times; the ex-trig loop was just used in June 2026 Very high (topic), moderate (form)
9 Partial fractions feeding an integral or a differential equation; an improper fraction is a real possibility in an October paper 17 of 18 papers; all three improper cases were October papers (2020, 2021, 2024) Very high (topic), moderate (improper)
10 Connected rates of change, most likely a sphere, a cone or a container with V(h), possibly leading into a differential equation 13 of 18; never absent from two sessions running since 2021 High
11 Proof by contradiction, 4–6 marks; the family is the least predictable item on the paper Every paper; irrational roots have not appeared since June 2023, the longest gap of any family; never-meets was just used in June 2026 Very high (topic), low (family)
  • A likely paper shape: 9 or 10 questions, opening with binomial (6–9 marks), with implicit (8–10), partial fractions or substitution (6–8 each), parametric (9–12), vectors (8–12), a differential equation (6–10), a volume (6–9), rates (4–7) and proof (4–6).
  • Less likely, but not to be skipped: a Cartesian area under a curve (3 times, last in October 2021), reflection of a point in a line (twice, last in June 2023), log differentiation of x^(f(x)) (once, October 2020).
  • Exam technique that the recent papers reward: full algebraic working on no-calculator questions (3–4 a paper now), exact forms, and the final substitution step in condition questions.

Appendix: every question

All 166 questions with their marks, topic tags and a one-line summary, newest session first.

January 2024 to June 2026

Session Q Marks Topic What it asks
Jun 2026 1 9 Partial fractions + binomial (2 + 11x)/((1 + x)(2 + 5x)) into partial fractions, expand to x2, validity
Jun 2026 2 6 Vectors + proof Lines not parallel; prove by contradiction that they do not meet
Jun 2026 3 11 Parametric x = 4/(t + 2), y = 6t/(t + 4): tangent at t = 2; Cartesian form; range
Jun 2026 4 7 Rates Container V = (1/3)h2√(h + 4): time to fill; dh/dt at h = 5
Jun 2026 5 9 Vectors Angle BAC; area of ABC; D on AB extended with angle ADC = 90°
Jun 2026 6 10 Implicit 4xy2 + 12y + 6x = 53: dy/dx; maximum value of x
Jun 2026 7 13 Parts + substitution ∫e^(2x) cos 4x dx (loop); ∫2x3/√(1 − 4x2) dx with 2x = sin u
Jun 2026 8 10 Differential equation Algae: a non-DE model, then dS/dt = (128 − S)/50; maximum area
Jan 2026 1 8 Binomial (1 + ax)^n from given coefficients: a, n and p; validity
Jan 2026 2 5 Parts ∫ from 2 to 2e2 of x3 ln(x/2) dx
Jan 2026 3 5 Proof Factorise x2 − 4y2; no positive integers with x2 − 4y2 = 27
Jan 2026 4 9 Substitution + partial fractions u = ex + 4 on ∫(2ex + 3)/(ex + 4) dx from 0 to ln 6
Jan 2026 5 11 Parametric x = (4t − 5)/(2t + 1), y = 2t2 − 4t + 4: point, dy/dx, tangent, domain and range
Jan 2026 6 10 Vectors Point on l1 nearest O; constant so the lines meet; intersection
Jan 2026 7 9 Implicit x2 tan y + 32y2/π2 = 11: gradient at P; tangent gradient × normal gradient
Jan 2026 8 10 Rates + differential equation Deflating balloon: dr/dt = −k/r2; r(t); time until V = 0
Jan 2026 9 8 Volume (parametric) x = 6 sin t, y = 5 sin 2t rotated: 80π
Oct 2025 1 7 Binomial (2 + 5x)^−2 to x3; validity; a related quadratic approximation
Oct 2025 2 5 Volume Cartesian curve between x = 2 and x = 8
Oct 2025 3 7 Parametric x = (t + 15)/(t + 4), y = 5/(t + 2): Cartesian form; range
Oct 2025 4 10 Implicit 4x2 + y2 − 2xy = 24x: gradient 2 at P(a, b)
Oct 2025 5 6 Vectors Constant β so the lines meet; intersection
Oct 2025 6 7 Substitution u = 3 + cos θ on ∫sin 2θ/√(3 + cos θ) dθ
Oct 2025 7 6 Vectors Parallelogram: exact cos θ; area 5√k
Oct 2025 8 6 Differential equation dV/dt = 12te^(−t) by parts; will the container ever fill?
Oct 2025 9 15 Parametric + area x = ln(2t + 5), y = 1/(t + 1): gradient −4; area by partial fractions
Oct 2025 10 6 Proof Odd squares; no integers with a2 − 4b = 27
Jun 2025 1 8 Implicit 2y2 − 6xy = 7e^(2x − 1) + 13: tangent at P
Jun 2025 2 4 Rates Melting ice ball: dr/dt inversely proportional to r2
Jun 2025 3 6 Differential equation dy/dx = 3 sin 2x/(y cos22x): y2 = 3 sec 2x + 10
Jun 2025 4 8 Partial fractions Three linear factors; ∫ from 2 to 4 = 5 ln 2 + 4 ln(3/5)
Jun 2025 5 9 Parametric x = (3 + 2t)/(1 − t), y = 1 − t2: normal; Cartesian form
Jun 2025 6 8 Vectors Line AB; α with angle BAC = 45°
Jun 2025 7 6 Substitution u = tan x; reverse chain rule
Jun 2025 8 10 Binomial (4 ± x)^(−1/2); product; approximation to √135
Jun 2025 9 12 Volume + parts y = cos x + ex/5; ∫ex cos x dx; paperweight volume
Jun 2025 10 4 Proof cos 2x/(cos x − sin x) < 1 for 90° < x < 180°
Jan 2025 1 5 Volume y = 4/(x + 2), 0 ≤ x ≤ 8: 32π/5
Jan 2025 2 8 Implicit 3x + 5y2 + 4x2y = 10(2^x) + 35: gradient at P on the y-axis
Jan 2025 3 8 Binomial 6(4 + Ax)^(−1/2): A, B and C; validity; x3 coefficient
Jan 2025 4 10 Rates + differential equation Balloon dr/dt at r = 5; dh/dt = k/h3, find T
Jan 2025 5 10 Parts + partial fractions ∫x2e^(4x) dx; ∫(2x + 11)/((2x + 1)(2 − x)) dx = ln k
Jan 2025 6 4 Proof If n2 − 4n + 5 is even then n is odd
Jan 2025 7 6 Substitution x = 4 sin θ on ∫1/(16 − x2)^(3/2) dx
Jan 2025 8 12 Vectors a and b; AB; angle CAB; two positions of D by area
Jan 2025 9 12 Parametric x = 2 cos 2t, y = sin3t: tangent; where it meets the curve again
Oct 2024 1 6 Binomial (8 − 3x)^(−1/3); rational approximation to ∛6
Oct 2024 2 4 Proof x4 + 10x2 + 8 and 2x2 − 7 never meet
Oct 2024 3 9 Parametric x = 3 sin3θ, y = 1 + cos 2θ: dy/dx; tangent; Cartesian
Oct 2024 4 9 Implicit 3x2 + 2y2 − 4xy + 8^x − 11 = 0: normal meets the x-axis
Oct 2024 5 6 Rates Inverted cone V = 4πh3/75; dh/dt after 1.5 minutes
Oct 2024 6 5 Substitution u = √(x3 + 1) on ∫9x5/√(x3 + 1) dx
Oct 2024 7 8 Partial fractions + volume (3x − 1)/(x + 2) = 3 − 7/(x + 2); volume π(p + q ln 2)
Oct 2024 8 10 Vectors Line AB; p and q so the lines meet at B; exact cos θ; length AC
Oct 2024 9 10 Partial fractions + differential equation Fairground ride; time of the third maximum
Oct 2024 10 8 Area (parametric) + parts x = 3t2, y = sin t sin 2t: area pπ + q
Jun 2024 1 5 Parts ∫ from 0 to π/6 of x cos 3x dx
Jun 2024 2 6 Vectors Coordinates of B; a with OC ⊥ BC
Jun 2024 3 7 Implicit 8x3 − 3y2 + 2xy = 9: normal at (2, 5)
Jun 2024 4 6 Rates Circle segment: dA/dθ = K(1 − cos θ); dA/dt
Jun 2024 5 13 Parametric + area + partial fractions x = t2 + 2t, y = 2/(t(3 − t)): end points; area with y = 1
Jun 2024 6 10 Vectors |OA| = 5√10: quadratic in λ; area of OAB
Jun 2024 7 11 Differential equation Current: dx/dt = k − 3x; k from the long-term value; time to 5 A
Jun 2024 8 8 Binomial + proof (8 − 3x)^(4/3); a line and a curve do not meet
Jun 2024 9 9 Substitution + volume tan u = √x; volume 2
Jan 2024 1 4 Binomial (1 − 4x)^−3 to x3
Jan 2024 2 10 Partial fractions Repeated factor; ∫ = p ln q + r
Jan 2024 3 9 Implicit y2x + 3y = 4x2 + k: minimum point P(p, 2)
Jan 2024 4 5 Rates Cone of fixed height: dS/dt at r = 1.5
Jan 2024 5 9 Parts + differential equation ∫x2 cos 2x dx; dy/dt = t2cos2t/y2
Jan 2024 6 14 Vectors p so the lines meet; intersection; acute angle; foot B
Jan 2024 7 8 Substitution + volume u = 4x + 2 sin 2x; volume
Jan 2024 8 4 Proof y = 2x + x3 + cos x has no stationary points
Jan 2024 9 12 Parametric x = sec t, y = √3 tan(t + π/3): dy/dx; tangent; Cartesian

October 2020 to October 2023

Session Q Marks Topic What it asks
Oct 2023 1 5 Binomial (2 − 5x)^−2; validity
Oct 2023 2 7 Rates Cube: dx/dt = 1/(3x); dV/dt = V^(1/3)
Oct 2023 3 12 Parts + substitution ∫x2e^(2x) dx exactly; ∫4x/(2x − 1)2 dx with the student’s own substitution
Oct 2023 4 5 Proof k + 9/k ≥ 6 for k > 0; not true for all real k
Oct 2023 5 10 Implicit y3 − x2 + 4x2y = k: the normal y = x gives k = 36
Oct 2023 6 10 Vectors Intersection P; cos θ; isosceles triangle area; positions of R
Oct 2023 7 12 Partial fractions + differential equation Goats: a non-DE model, then dx/dt = x(9 − 2x)/3
Oct 2023 8 14 Parametric + volume x = 6t − 3 sin 2t, y = 2 cos t: dy/dx; tangent; volume
Jun 2023 1 9 Binomial (1/4 − x/2)^(−3/2); a related expansion
Jun 2023 2 10 Implicit 2^x − 4xy + y2 = 13: tangent meets the x-axis
Jun 2023 3 11 Partial fractions (8x − 5)/((2x − 1)(4x − 3)); integral; find k
Jun 2023 4 10 Vectors Line AB; foot C; reflection P′; |PP′|
Jun 2023 5 10 Parts + substitution ∫x2ex dx; u = √(1 − 3x) on ∫27x/√(1 − 3x) dx
Jun 2023 6 9 Differential equation Engine cooling dθ/dt = −k(θ − 15); time to 20 °C
Jun 2023 7 4 Proof √7 is irrational
Jun 2023 8 12 Parametric + volume x = t + 1/t, y = t − 1/t: normal; volume with a cone
Jan 2023 1 9 Partial fractions + binomial (5x + 10)/((1 − x)(2 + 3x)); expand; validity
Jan 2023 2 6 Parametric Points lie on a straight line; meet y = x + 12
Jan 2023 3 5 Volume y2 = 3x/(3x2 + 5): a ln b
Jan 2023 4 9 Substitution + parts u = √(2x + 1); ∫2u2eu du = 34e5 − 10e3
Jan 2023 5 7 Implicit y2 = 2x2 + 15x + 10y: interval where the curve is undefined
Jan 2023 6 8 Vectors Line AB; foot P from C
Jan 2023 7 12 Differential equation + rates Balloon: V = 300t/(2t + 3); limit; r and dr/dt at t = 3
Jan 2023 8 11 Parametric + area x = sin2t, y = 2 tan t: normal; area of S
Jan 2023 9 8 Proof Complete the p3 proof; ∛3 is irrational
Oct 2022 1 3 Parametric x = t/(t − 3), y = 1/t + 2: Cartesian form
Oct 2022 2 7 Partial fractions 3x/((2x − 1)(x − 2)); ∫ = ln k
Oct 2022 3 5 Vectors RQ; angle PQR
Oct 2022 4 8 Binomial (4 − x2)^(−1/2); validity; √3 approximation
Oct 2022 5 6 Volume y = 12√x/(2x2 + 3)^1.5; find k from V = 713π/648
Oct 2022 6 8 Parametric x = 1 + 3 tan t, y = 2 cos 2t: tangent; k; range
Oct 2022 7 12 Substitution + parts u = ex − 3 gives a + b ln 2; ∫3ex cos 2x dx (loop)
Oct 2022 8 4 Proof No positive integers with 3x2 + 2xy − y2 = 25
Oct 2022 9 5 Vectors Prove the lines are skew
Oct 2022 10 8 Differential equation Melting ice ball dr/dt = −k/r2; time to melt; sketch
Oct 2022 11 9 Implicit (x + y)3 + 10y2 = 108x: furthest point south
Jun 2022 1 7 Binomial (3 + kx)^−2: k = −6; x3 coefficient
Jun 2022 2 9 Partial fractions + differential equation cot y dy/dx = 1/((1 + 3x)(1 − x))
Jun 2022 3 8 Rates Circle area decreasing; cylinder volume
Jun 2022 4 8 Implicit 16x3 − 9kx2y + 8y3 = 875: stationary point, k = 4/3
Jun 2022 5 8 Substitution x = 2 sin u: 7√3/6 − 3/2
Jun 2022 6 9 Vectors Line AB; p = −8 from AC ⊥ AB; area 9√10
Jun 2022 7 12 Parametric Gradient 3 at t = π; tangent y = 3x + 7; meets the curve again
Jun 2022 8 10 Volume + parts y = 10xe^(−x/2); density 3.99 g/cm3
Jun 2022 9 4 Proof n2 − 2 is never divisible by 4
Jan 2022 1 6 Implicit xy2 = x2y + 6: tangent at (2, 3)
Jan 2022 2 7 Binomial (1 + 4x3)^(1/3); ∛31
Jan 2022 3 9 Parametric + partial fractions x = 3 + 2 sin t, y = 6/(7 + cos 2t): Cartesian form; partial fractions
Jan 2022 4 8 Rates Icosahedron: dV/dA; dV/dt at x = 2
Jan 2022 5 10 Area (parametric) + substitution x = √(9 − 4t), y = t3/√(9 + 4t); u = 81 − 16t2
Jan 2022 6 5 Proof k, 1 + 2k, 3 + 3k is not a geometric sequence
Jan 2022 7 8 Volume + parts Doorknob: (π/16)∫(x2 − 8x + 16)e^(2x) dx
Jan 2022 8 11 Vectors Line AB; the lines do not meet; acute angle
Jan 2022 9 11 Differential equation 3 cosec 2x · dy/dx = y(1 + 2 ln y)3, with a signposted derivative
Oct 2021 1 7 Implicit 2x − 4y2 + 3x2y = 4x2 + 8: normal at (3, 2)
Oct 2021 2 6 Differential equation dy/dx = 4y2/√(4x + 5): y = 1/(7 − 2√(4x + 5))
Oct 2021 3 8 Partial fractions Improper g(x); show g′(x) > 3
Oct 2021 4 6 Binomial (1 − 4x2)^(1/2); √3 ≈ 1.7324
Oct 2021 5 9 Parametric x = 5 + 2 tan t, y = 8 sec2t: gradient; Cartesian; range
Oct 2021 6 7 Substitution + area u = 3 + 4 sin x: ln(49/25) − 12/35
Oct 2021 7 9 Vectors Foot X; distance √67; reflection
Oct 2021 8 7 Parts + volume ∫x2 ln x dx; volume of y = x ln x
Oct 2021 9 10 Rates + differential equation Tank: dh/dt = (12 − 3h)/320; about 208 minutes
Oct 2021 10 6 Proof Complete the n3 proof; ∛2 is irrational
Jun 2021 1 7 Binomial √(1 + kx): k, A and B; √1.15
Jun 2021 2 7 Volume y = 9/(2x − 3)^1.25 with y = 9 and x = 6: 298π
Jun 2021 3 7 Rates Bowl: time to fill 20 s; dh/dt = 96/23
Jun 2021 4 8 Substitution + partial fractions u = √x: 4 ln(14/9)
Jun 2021 5 9 Implicit y2 = ye^(−2x) − 3x: tangents meet at R
Jun 2021 6 10 Parametric + area x = 2 cos 2t, y = 4 sin t: area 8√2/3; Cartesian; range
Jun 2021 7 10 Vectors Unit vector; closest point to O; area √101/2
Jun 2021 8 9 Differential equation + parts dy/dx = 6xe^(−2x)y^(1/3); asymptote
Jun 2021 9 8 Vectors + proof c = 3b − 2a; if n2 is a multiple of 3, so is n
Jan 2021 1 7 Binomial √(1 − 20x); √5
Jan 2021 2 5 Vectors Angle ABC; parallelogram area
Jan 2021 3 2 Proof There is no greatest odd integer
Jan 2021 4 7 Parametric Cartesian g(x) = (x − 4)/(3x − 5); range
Jan 2021 5 8 Substitution u = 3 + √(2x − 1): p + q ln 2
Jan 2021 6 9 Implicit 4y2 + 3x = 6ye^(−2x): normal at P
Jan 2021 7 7 Parts + area ∫e^(2x) sin x dx; area (e^(2π) + 1)/5
Jan 2021 8 6 Vectors Skew for every b ≠ 7
Jan 2021 9 10 Volume (parametric) x = tan θ, y = 2 sin 2θ: 8π2/3 − 2√3π
Jan 2021 10 14 Partial fractions + differential equation Tank depth; time to 8 m; long-term depth 5 m
Oct 2020 1 4 Proof If n3 is even, n is even
Oct 2020 2 8 Binomial (4 − 5x)^(−1/2); k and m
Oct 2020 3 6 Volume y = e^(0.5x) − 2: 8π ln 2 − 5π
Oct 2020 4 12 Parametric Tangent at B; where it meets the curve again
Oct 2020 5 7 Parts + area ∫ln x/x2 dx; area 1 + 2 ln 2
Oct 2020 6 7 Implicit y = x^(sin x) by logs; stationary points
Oct 2020 7 12 Substitution + partial fractions ∫3x/√(2x − 1) dx = 16; improper partial fractions
Oct 2020 8 10 Vectors Intersection; foot Q
Oct 2020 9 9 Differential equation Bacteria; limiting area 900/361