WMA14 P4: full past-paper analysis, Oct 2020 to Jun 2026 with October 2026 predictions
Edexcel IAL Pure Mathematics 4 (WMA14). 18 papers, updated 4 October 2026.
Headline findings
WMA14 is highly predictable by topic: seven of the eleven topics scored marks in all 18 papers, and even the least regular, connected rates of change, scored in 13. The strongest single signal for October 2026 is a volume of revolution, because June 2026 was the first paper without one after 17 in a row.
- Vectors are the largest topic at 10.7 marks a paper (range 8–16), and five routines cover almost every part: lines meeting, angle, foot of a perpendicular, area, reflection.
- Close to 30 of the 75 marks need integration, spread across substitution, parts, partial fractions, volumes and differential equations.
- LIATE picks u correctly in all 19 integration-by-parts integrals: logarithm 4, algebraic 11, and 4 ex-times-trig loops where either choice works.
- Binomial opens 11 of the 18 papers, and since June 2022 the bracket has started with a number other than 1 in 11 of 13.
- Question styles are shifting: gradient-condition follow-ups in implicit differentiation (7 of the last 13), rational parametric curves (4 of the 6 since June 2025), cross-topic proofs (5 of the last 9), and twice as many no-calculator notices since January 2025 (3.6 a paper, up from 1.85).
- October-only pattern: all three improper partial-fraction questions fell in October papers (2020, 2021, 2024).
- Grade boundary for reference: in October 2024 an A needed 52/75 and the a* 58/75 (Pearson).
Scope and method
This analysis covers every WMA14 paper from October 2020 to June 2026: 18 papers, 166 questions and 1,350 marks, each read with its mark scheme.
- Sessions: October 2020; January, June and October of 2021 to 2025; January and June 2026. There are no gaps in that window.
- One relabelled paper: the question paper labelled “2020 May” is printed June 2020, but its mark scheme is the October 2020 one (WMA14_01_2010_MS). It is treated here as October 2020.
- Tagging: every question part was assigned to the skill its marks test, using the part marks printed on the paper. Every paper sums to exactly 75.
- Mixed parts: where one part tests two skills (a volume finished by integration by parts, say), its marks went to the skill doing most of the work. Read per-topic mark figures as roughly ±2.
- Technique detail (the choice of u in parts, the substitution, the binomial power, the form of a differential equation, the vector task) comes from each mark scheme’s main method, not from alternatives.
- Eleven topic rows are used throughout: vectors, parametric equations, implicit differentiation, differential equations, volumes and areas, binomial expansion, integration by substitution, partial fractions, proof by contradiction, connected rates of change, and integration by parts.
Paper structure
Every paper is 75 marks over 8 to 11 questions (166 in all, 8.1 marks on average). Binomial expansion opens 11 of the 18 papers, and the last question is parametric, proof or a differential equation in 16 of 18.
| Session | Questions | Question 1 (marks) | Largest question (marks) | Last question (marks) | No-calculator notices |
|---|---|---|---|---|---|
| Jun 2026 | 8 | Partial fractions, then binomial (9) | Q7 parts + substitution (13) | Q8 differential equation, algae (10) | 4 |
| Jan 2026 | 9 | Binomial, find a and n (8) | Q5 parametric (11) | Q9 parametric volume (8) | 2 |
| Oct 2025 | 10 | Binomial (2 + 5x)^−2 (7) | Q9 parametric gradient + area (15) | Q10 proof, odd squares (6) | 4 |
| Jun 2025 | 10 | Implicit, tangent (8) | Q9 volume, paperweight (12) | Q10 proof, trig inequality (4) | 4 |
| Jan 2025 | 9 | Volume of revolution (5) | Q8 vectors and Q9 parametric (12 each) | Q9 parametric, tangent meets curve again (12) | 4 |
| Oct 2024 | 10 | Binomial (8 − 3x)^(−1/3) (6) | Q8 vectors and Q9 differential equation (10 each) | Q10 parametric area (8) | 2 |
| Jun 2024 | 9 | Parts, ∫x cos 3x (5) | Q5 parametric area + partial fractions (13) | Q9 volume by substitution (9) | 2 |
| Jan 2024 | 9 | Binomial (1 − 4x)^−3 (4) | Q6 vectors (14) | Q9 parametric (12) | 0 |
| Oct 2023 | 8 | Binomial (2 − 5x)^−2 (5) | Q8 parametric + volume (14) | Q8, as largest | 1 |
| Jun 2023 | 8 | Binomial (1/4 − x/2)^(−3/2) (9) | Q8 parametric + volume (12) | Q8, as largest | 1 |
| Jan 2023 | 9 | Partial fractions, then binomial (9) | Q7 balloon, differential equation + rates (12) | Q9 proof, ∛3 irrational (8) | 3 |
| Oct 2022 | 11 | Parametric to Cartesian (3) | Q7 substitution + parts (12) | Q11 implicit, cycle track (9) | 3 |
| Jun 2022 | 9 | Binomial (3 + kx)^−2 (7) | Q7 parametric (12) | Q9 proof, n2 − 2 (4) | 4 |
| Jan 2022 | 9 | Implicit, tangent (6) | Q8 vectors and Q9 differential equation (11 each) | Q9 differential equation (11) | 1 |
| Oct 2021 | 10 | Implicit, normal (7) | Q9 tank, rates + differential equation (10) | Q10 proof, ∛2 irrational (6) | 2 |
| Jun 2021 | 9 | Binomial √(1 + kx) (7) | Q6 parametric and Q7 vectors (10 each) | Q9 vectors + proof (8) | 1 |
| Jan 2021 | 10 | Binomial √(1 − 20x) (7) | Q10 partial fractions + differential equation (14) | Q10, as largest | 3 |
| Oct 2020 | 9 | Proof, n3 even (4) | Q4 parametric and Q7 integration (12 each) | Q9 differential equation, bacteria (9) | 1 |
- Question 1: binomial in 11 papers (twice preceded by partial fractions), implicit differentiation in 3 (Oct 2021, Jan 2022, Jun 2025), and once each proof, a parametric-to-Cartesian conversion, integration by parts and a volume.
- Largest question: parametric work (including parametric areas and volumes) is the largest, or joint largest, in 9 papers; vectors in 5. The single biggest question in the set is October 2025 Q9 at 15 marks.
- Last question: parametric in 6 papers, proof in 6 (Jun 2021’s vectors question ends in a proof part), a differential equation in 4, implicit and a volume once each.
- Question sizes run from 2 marks (Jan 2021 Q3, no greatest odd integer) to 15. Papers with 8 questions (Jun 2023, Oct 2023, Jun 2026) carry more 10+ mark questions.
- No-calculator notices count the “Solutions relying (entirely) on calculator technology are not acceptable” lines. They averaged 1.85 a paper from Oct 2020 to Oct 2024, and 3.6 a paper across the five papers since January 2025.
Marks by topic in every paper
Every topic scores in nearly every paper; vectors lead at 10.7 marks a paper
Marks per topic in each WMA14 paper, October 2020 to June 2026, sorted by average. Darker cells mean more marks; a dash means none. The outlined column is June 2026, the paper before October 2026.
| Topic | Oct 20 | Jan 21 | Jun 21 | Oct 21 | Jan 22 | Jun 22 | Oct 22 | Jan 23 | Jun 23 | Oct 23 | Jan 24 | Jun 24 | Oct 24 | Jan 25 | Jun 25 | Oct 25 | Jan 26 | Jun 26 | Avg |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| Vectors | 10 | 11 | 13 | 9 | 11 | 9 | 10 | 8 | 10 | 10 | 14 | 16 | 10 | 12 | 8 | 12 | 10 | 10 | 10.7 |
| Parametric | 12 | 7 | 4 | 9 | 6 | 12 | 11 | 11 | 5 | 8 | 12 | 2 | 9 | 12 | 9 | 13 | 11 | 11 | 9.1 |
| Implicit | 7 | 9 | 9 | 7 | 6 | 8 | 9 | 7 | 10 | 10 | 9 | 7 | 9 | 8 | 8 | 10 | 9 | 10 | 8.4 |
| Differential equations | 9 | 11 | 9 | 12 | 11 | 6 | 8 | 8 | 9 | 9 | 5 | 11 | 8 | 6 | 6 | 6 | 7 | 10 | 8.4 |
| Volumes and areas | 10 | 12 | 13 | 4 | 7 | 7 | 6 | 11 | 7 | 6 | 3 | 8 | 9 | 5 | 8 | 9 | 8 | – | 7.4 |
| Binomial | 8 | 7 | 7 | 6 | 7 | 7 | 8 | 6 | 9 | 5 | 4 | 4 | 6 | 8 | 10 | 7 | 8 | 6 | 6.8 |
| Substitution | 6 | 8 | 8 | 7 | 6 | 8 | 7 | 4 | 6 | 7 | 5 | 6 | 5 | 6 | 6 | 7 | 3 | 7 | 6.2 |
| Partial fractions | 6 | 3 | – | 8 | 3 | 3 | 7 | 3 | 11 | 3 | 10 | 6 | 4 | 6 | 8 | 5 | 6 | 3 | 5.3 |
| Proof | 4 | 2 | 5 | 6 | 5 | 4 | 4 | 8 | 4 | 5 | 4 | 4 | 4 | 4 | 4 | 6 | 5 | 5 | 4.6 |
| Rates of change | – | – | 7 | 4 | 8 | 8 | – | 4 | – | 7 | 5 | 6 | 6 | 4 | 4 | – | 3 | 7 | 4.1 |
| Integration by parts | 3 | 5 | – | 3 | 5 | 3 | 5 | 5 | 4 | 5 | 4 | 5 | 5 | 4 | 4 | – | 5 | 6 | 3.9 |
Read across a row for how steady a topic is, and down a column for one paper’s mix. Rates of change is missing from five papers, integration by parts from two (both times it sat inside a differential equation), and volumes and areas only from June 2026.
Binomial expansion
A binomial question appears in all 18 papers (6.8 marks on average, range 4–10), and it is Question 1 in 11 of them. Since June 2022 the bracket has started with a number other than 1 in 11 of 13 papers, so taking out an is now routine.
| Session (question, marks) | Expression | Power n | Take out an | Tasks | Validity asked |
|---|---|---|---|---|---|
| Jun 2026 (Q1b–c, 6) | (2 + 11x)/((1 + x)(2 + 5x)) = 3/(1 + x) − 4/(2 + 5x) | −1, twice | Yes, 2^−1 | Expand each fraction and add: 1 + 2x − 19x2/2 | Yes, |x| < 2/5 |
| Jan 2026 (Q1, 8) | (1 + ax)^n = 1 − 4x + (24/5)x2 + px3 | 5/2, found | No | Two equations in a and n, then p | Yes, |x| < 5/8 |
| Oct 2025 (Q1, 7) | (2 + 5x)^−2 | −2 | Yes, 1/4 | 4 terms; then a + bx + cx2 for a related fraction | Yes, |x| < 2/5 |
| Jun 2025 (Q8, 10) | (4 + x)^(−1/2), then (4 − x)^(−1/2) | −1/2 | Yes, 1/2 | 3 terms; swap x for −x; multiply to a + bx2; x = 1 gives √135 | No |
| Jan 2025 (Q3, 8) | 6(4 + Ax)^(−1/2) = B − x/4 + Cx2 + … | −1/2 | Yes, 1/2 | Find A = 2/3, B = 3, C = 1/32; then the x3 coefficient | Yes, |x| < 6 |
| Oct 2024 (Q1, 6) | (8 − 3x)^(−1/3) | −1/3 | Yes, 1/2 | 4 terms; x = 2/3 gives a rational approximation to ∛6 | No |
| Jun 2024 (Q8a, 4) | (8 − 3x)^(4/3) | 4/3 | Yes, 16 | Show 16 − 8x + x2/2 + x3/24, then used in a proof | No |
| Jan 2024 (Q1, 4) | (1 − 4x)^−3 | −3 | No | Up to x3 | No (given) |
| Oct 2023 (Q1, 5) | (2 − 5x)^−2 | −2 | Yes, 1/4 | 4 terms | Yes, |x| < 2/5 |
| Jun 2023 (Q1, 9) | (1/4 − x/2)^(−3/2) | −3/2 | Yes, 8 | 8 + 24x + 60x2 + 140x3; then a related expansion | No (given) |
| Jan 2023 (Q1b, 6) | (5x + 10)/((1 − x)(2 + 3x)) = 3/(1 − x) + 4/(2 + 3x) | −1, twice | Yes, 2^−1 | Up to x2 | Yes, |x| < 2/3 |
| Oct 2022 (Q4, 8) | (4 − x2)^(−1/2) | −1/2 | Yes, 1/2 | First 4 non-zero terms; rational approximation for √3 | Yes, |x| < 2 |
| Jun 2022 (Q1, 7) | (3 + kx)^−2 | −2 | Yes, 1/9 | x2 coefficient = 3 × x coefficient gives k2 + 6k = 0, k = −6; x3 coefficient 32/9 | No |
| Jan 2022 (Q2, 7) | (1 + 4x3)^(1/3) | 1/3 | No | First 3 non-zero terms (x0, x3, x6); x = 1/3 gives ∛31 | No (given) |
| Oct 2021 (Q4, 6) | (1 − 4x2)^(1/2) | 1/2 | No | First 4 non-zero terms; x = 1/4 gives √3 ≈ 1.7324 | No (given) |
| Jun 2021 (Q1, 7) | (1 + kx)^(1/2) | 1/2 | No | k = 1/4 from the x coefficient; A, B; √1.15 to 6 d.p. | No |
| Jan 2021 (Q1, 7) | (1 − 20x)^(1/2) | 1/2 | No | 4 terms; x = 1/100 gives √5 as a/b | No (given) |
| Oct 2020 (Q2, 8) | (4 − 5x)^(−1/2), then (2 + kx)(…) | −1/2 | Yes, 1/2 | 3 terms; compare coefficients for k = −13/20, m = 49/128 | No (given) |
- Powers: −1/2 four times, 1/2 three, −2 three, −1 twice (via partial fractions), and 1/3, −1/3, −3, −3/2, 4/3 and 5/2 once each. Positive integer powers never appear here; they belong to P2.
- Unknown constants in 5 papers (Oct 2020, Jun 2021, Jun 2022, Jan 2025, Jan 2026). Jan 2026 is the hardest form: two unknowns, eliminated by dividing (na)2 into n(n − 1)a2.
- Approximations in 7 papers, always a root: √5, √1.15, √3 twice, ∛31, ∛6, √135. Students must pick the x that turns the bracket into the target and check it is in range.
- Validity is asked in 7 papers, including 4 of the last 5. The rest print the range in the stem.
- Inner term in x2 or x3 (Oct 2021, Jan 2022, Oct 2022) changes “first n terms” into “first n non-zero terms” and doubles or triples the powers.
- Near-repeat: Oct 2023 Q1 is (2 − 5x)^−2 and Oct 2025 Q1 is (2 + 5x)^−2.
- Combined uses: partial fractions then expansion (Jan 2023, Jun 2026), a product with a polynomial (Oct 2020), a product of two expansions (Jun 2025), and an expansion feeding a proof (Jun 2024).
Partial fractions
Partial fractions appear in all 18 papers: 19 decompositions in total, examined as their own part in 17 papers (June 2021 hides one inside a substitution). Fourteen are two distinct linear factors; the decomposition is almost never the end goal, because 17 of the 19 feed an integral, a differential equation or an expansion.
| Session (question) | Fraction | Form | Fed into |
|---|---|---|---|
| Jun 2026 (Q1a) | (2 + 11x)/((1 + x)(2 + 5x)) = 3/(1 + x) − 4/(2 + 5x) | Distinct | Binomial expansion |
| Jan 2026 (Q4b) | (2u − 5)/(u(u − 4)) = 5/(4u) + 3/(4(u − 4)) | Distinct, in u | Definite integral after u = ex + 4, giving P ln 2 + Q ln 3 |
| Oct 2025 (Q9b) | k/((t + 1)(2t + 5)) | Distinct, in t | Parametric area, answer ln α |
| Jun 2025 (Q4) | (5 + 17x − 10x2)/(x(1 − x)(2x + 1)) = 5/x + 4/(1 − x) + 8/(2x + 1) | Three distinct factors | Definite integral, 5 ln 2 + 4 ln(3/5) |
| Jan 2025 (Q5ii) | (2x + 11)/((2x + 1)(2 − x)) | Distinct | Definite integral, ln k |
| Oct 2024 (Q9a) | 1/(x(2x − 1)) = 2/(2x − 1) − 1/x | Distinct | Differential equation (fairground ride) |
| Oct 2024 (Q7a) | (3x − 1)/(x + 2) = 3 − 7/(x + 2) | Improper, linear over linear | Volume, π(p + q ln 2) |
| Jun 2024 (Q5c) | (t + 1)/(t(3 − t)) = 1/(3t) + 4/(3(3 − t)) | Distinct, in t | Parametric area |
| Jan 2024 (Q2) | (3x + 4)/((x − 2)(2x + 1)2) = 2/(5(x − 2)) − 4/(5(2x + 1)) − 1/(2x + 1)2 | Repeated factor | Definite integral, p ln q + r |
| Oct 2023 (Q7c) | 3/(x(9 − 2x)) = 1/(3x) + 2/(3(9 − 2x)) | Distinct | Differential equation (goats) |
| Jun 2023 (Q3) | (8x − 5)/((2x − 1)(4x − 3)) = 1/(2x − 1) + 2/(4x − 3) | Distinct | Integral, then solve for a limit k |
| Jan 2023 (Q1a) | (5x + 10)/((1 − x)(2 + 3x)) = 3/(1 − x) + 4/(2 + 3x) | Distinct | Binomial expansion |
| Oct 2022 (Q2) | 3x/((2x − 1)(x − 2)) = −1/(2x − 1) + 2/(x − 2) | Distinct | Definite integral, ln k |
| Jun 2022 (Q2a) | 1/((1 + 3x)(1 − x)) = 3/(4(1 + 3x)) + 1/(4(1 − x)) | Distinct | Differential equation, sin4y = (1 + 3x)/(5(1 − x)) |
| Jan 2022 (Q3b) | 12/((7 − x)(1 + x)) | Distinct | Rewriting a Cartesian equation as a/(x + b) + c/(x + d) |
| Oct 2021 (Q3) | (3x3 + 8x2 − 3x − 6)/(x(x + 3)) = 3x − 1 − 2/x + 2/(x + 3) | Improper, cubic over quadratic | Differentiate, then argue g′(x) > 3 |
| Jun 2021 (Q4) | 20/(u(5 + 2u)) = 4/u − 8/(5 + 2u) | Distinct, in u | Definite integral after u = √x, 4 ln(14/9) |
| Jan 2021 (Q10a) | 1/((H − 5)(H + 3)) = (1/8)/(H − 5) − (1/8)/(H + 3) | Distinct | Differential equation (tank depth) |
| Oct 2020 (Q7ii) | (6x2 − 16)/((x + 1)(2x − 3)) = 3 + 2/(x + 1) − 1/(2x − 3) | Improper, quadratic over quadratic | Indefinite integral |
- Forms: 14 two-factor distinct, 3 improper (Oct 2020, Oct 2021, Oct 2024), 1 repeated factor (Jan 2024), 1 with three distinct factors (Jun 2025). All three improper cases fell in October sessions.
- What it fed: a definite or indefinite integral ending in logs 11 times, a differential equation 4, a binomial expansion 2, and once each a derivative argument and a Cartesian form.
- In a new variable: four decompositions were in u or t (Jun 2021, Jun 2024, Oct 2025, Jan 2026), so students meet partial fractions mid-way through a substitution or a parametric area, not only as part (a).
- The log step carries the marks: ∫1/(ax + b) dx = (1/a) ln|ax + b| and combining logs into the requested form (p ln q + r, ln k) are where the A marks sit.
Implicit differentiation
Implicit differentiation is in all 18 papers (8.4 marks on average, range 6–10). The product rule on an x-and-y term is needed in 17 of them, and since June 2022 the follow-up has moved from “tangent or normal at a point” towards “find the point where the gradient meets a condition” (7 of the last 13).
| Session (question, marks) | Curve | Terms that need care | Follow-up task |
|---|---|---|---|
| Jun 2026 (Q6, 10) | 4xy2 + 12y + 6x = 53 | Product | Maximum value of x: denominator 4xy + 6 = 0, substitute back for a and b |
| Jan 2026 (Q7, 9) | x2 tan y + 32y2/π2 = 11 | Product with a trig function of y | x at y = π/4; exact dy/dx at P; tangent gradient at P × normal gradient at Q |
| Oct 2025 (Q4, 10) | 4x2 + y2 − 2xy = 24x | Product | Gradient 2 at P(a, b): gives y = 12 − 2x, substitute back |
| Jun 2025 (Q1, 8) | 2y2 − 6xy = 7e^(2x−1) + 13 | Product, e^(ax+b) | Two y values at x = 1/2; tangent at the positive one, integer form |
| Jan 2025 (Q2, 8) | 3x + 5y2 + 4x2y = 10(2^x) + 35 | Product, a^x | dy/dx (6 marks); exact gradient at P on the y-axis |
| Oct 2024 (Q4, 9) | 3x2 + 2y2 − 4xy + 8^x − 11 = 0 | Product, a^x | Verify P(1, 2); normal meets the x-axis at a + b ln 2 |
| Jun 2024 (Q3, 7) | 8x3 − 3y2 + 2xy = 9 | Product | Normal at (2, 5), integer form |
| Jan 2024 (Q3, 9) | y2x + 3y = 4x2 + k | Product, unknown k | P(p, 2) is a minimum turning point: find p and k |
| Oct 2023 (Q5, 10) | y3 − x2 + 4x2y = k | Product, unknown k | Normal at P is y = x: gradient −1 at a point with y = x, so p = 2 and k = 36 |
| Jun 2023 (Q2, 10) | 2^x − 4xy + y2 = 13 | Product, a^x | y at x = 2; tangent meets the x-axis at (a ln 2 + b)/(c ln 2 + d) |
| Jan 2023 (Q5, 7) | y2 = 2x2 + 15x + 10y | None | Curve not defined on (p, q): vertical tangents where y = 5 |
| Oct 2022 (Q11, 9) | (x + y)3 + 10y2 = 108x | Chain rule on a bracket | Show dy/dx; furthest point south (dy/dx = 0), to the nearest 100 m |
| Jun 2022 (Q4, 8) | 16x3 − 9kx2y + 8y3 = 875 | Product, unknown k | Stationary point at x = 5/2: ky = 20/3, back into the curve, k = 4/3 |
| Jan 2022 (Q1, 6) | xy2 = x2y + 6 | Product twice | Tangent at (2, 3), integer form |
| Oct 2021 (Q1, 7) | 2x − 4y2 + 3x2y = 4x2 + 8 | Product | Normal at (3, 2): 11x − 14y − 5 = 0 |
| Jun 2021 (Q5, 9) | y2 = ye^(−2x) − 3x | Product, e^(kx) | Show dy/dx; tangents at O and at P on the y-axis meet at R(1/8, 3/8) |
| Jan 2021 (Q6, 9) | 4y2 + 3x = 6ye^(−2x) | Product, e^(kx) | dy/dx; normal at P on the y-axis as y = mx + c |
| Oct 2020 (Q6, 7) | y = x^(sin x) | Take logs first | dy/dx; stationary points satisfy tan x + x ln x = 0 |
- Follow-up tasks: a tangent or normal at a point 8 times (two of them then meet an axis); dy/dx = 0 four times (Oct 2020, Jun 2022, Oct 2022, Jan 2024); a vertical tangent twice (Jan 2023, Jun 2026); a given gradient twice (Oct 2023, Oct 2025); a gradient product once (Jan 2026).
- The condition questions share one route: set the numerator, the denominator or the gradient expression to the condition, get a link between x and y, then substitute that link into the curve. The last step carries 2–3 marks and is the one weaker students skip.
- a^x terms (2^x, 8^x) appear three times since June 2023, so d/dx(a^x) = a^x ln a from P3 is assumed, and answers come out in ln 2.
- Exponentials of x (e^(−2x), e^(2x−1)) appear three times (Jan 2021, Jun 2021, Jun 2025), always multiplied by y or on the right-hand side.
- Unknown constants in the curve (k) appear three times; each is found from the follow-up condition.
- Points on the y-axis (Jan 2021, Jun 2021, Jan 2025) need x = 0 in the curve before any differentiation.
Parametric equations
Every paper has a parametric question, 25 in all (9.1 marks a paper, range 2–13). Trigonometric parametrisations dominated to October 2024 (10 of 18 curves). Since June 2025, four of the six curves have been rational, such as x = 4/(t + 2), and three of those converted to a rational Cartesian form.
| Session (question, marks) | x and y | Type | Tasks |
|---|---|---|---|
| Jun 2026 (Q3, 11) | x = 4/(t + 2), y = 6t/(t + 4) | Rational | Tangent at t = 2; Cartesian f(x) = (12 − 6x)/(x + 2) on 0 < x < k; range of f |
| Jan 2026 (Q9, 8) | x = 6 sin t, y = 5 sin 2t | Trigonometric | Volume, see Volumes and areas |
| Jan 2026 (Q5, 11) | x = (4t − 5)/(2t + 1), y = 2t2 − 4t + 4, t ≥ 0 | Rational and quadratic | P(1, 10); dy/dx; tangent y = 28x − 18; domain −5 ≤ x < 2; range f(x) ≥ 2 |
| Oct 2025 (Q9, 15) | x = ln(2t + 5), y = 1/(t + 1) | Logarithmic | Point where the gradient is −4 (t = −1/4, y = 4/3); area for ln 9 ≤ x ≤ ln 15 |
| Oct 2025 (Q3, 7) | x = (t + 15)/(t + 4), y = 5/(t + 2) | Rational | Cartesian g(x) = (ax + b)/(cx + d) with its domain; range of g |
| Jun 2025 (Q5, 9) | x = (3 + 2t)/(1 − t), y = 1 − t2 | Rational and quadratic | Normal at t = 2, through (−7, −3); Cartesian y = (10x − 5)/(x + 2)2 |
| Jan 2025 (Q9, 12) | x = 2 cos 2t, y = sin3t | Trigonometric | dy/dx = −(3/8) sin t; tangent 3x + 16y − 5 = 0; where it meets the curve again |
| Oct 2024 (Q10, 8) | x = 3t2, y = sin t sin 2t | Polynomial and trigonometric | Area, see Volumes and areas |
| Oct 2024 (Q3, 9) | x = 3 sin3θ, y = 1 + cos 2θ | Trigonometric | dy/dx = k cosec θ; tangent 16x + 18y − 33 = 0; Cartesian 8x2 = 9(2 − y)3 |
| Jun 2024 (Q5, 13) | x = t2 + 2t, y = 2/(t(3 − t)) | Polynomial and rational | Ends on y = 1 (t = 1, 2); area between the curve and y = 1 |
| Jan 2024 (Q9, 12) | x = sec t, y = √3 tan(t + π/3) | Trigonometric, compound angle | dy/dx; tangent y = 2x − 7; Cartesian via the compound-angle formula and sec2t = 1 + tan2t |
| Oct 2023 (Q8, 14) | x = 6t − 3 sin 2t, y = 2 cos t | Trigonometric | k = 3π; dy/dx = −(1/6) cosec t; tangent meets the y-axis at N; volume |
| Jun 2023 (Q8, 12) | x = t + 1/t, y = t − 1/t | Rational | Q(2, 0); P(2.5, 1.5); normal 3x + 5y = 15; volume |
| Jan 2023 (Q8, 11) | x = sin2t, y = 2 tan t | Trigonometric | Normal at t = π/4: 2x + 8y = 17; area bounded by the curve, the normal and the x-axis |
| Jan 2023 (Q2, 6) | x = (t − 1)/(2t + 1), y = 6/(2t + 1) | Rational | Show the points lie on a straight line (y = 2 − 4x); meet y = x + 12 |
| Oct 2022 (Q6, 8) | x = 1 + 3 tan t, y = 2 cos 2t | Trigonometric | Tangent where the curve crosses the x-axis; domain end k; range of f |
| Oct 2022 (Q1, 3) | x = t/(t − 3), y = 1/t + 2 | Rational | Cartesian y = (7x − 1)/(3x) |
| Jun 2022 (Q7, 12) | x = sin t − 3cos2t, y = 3 sin t + 2 cos t | Trigonometric | Gradient 3 at t = π; tangent y = 3x + 7; meets the curve again where 9cos2t + 2 cos t − 7 = 0 |
| Jan 2022 (Q5, 10) | x = √(9 − 4t), y = t3/√(9 + 4t) | Roots | Area, see Volumes and areas |
| Jan 2022 (Q3, 9) | x = 3 + 2 sin t, y = 6/(7 + cos 2t) | Trigonometric | Cartesian y = 12/((7 − x)(1 + x)) on 1 ≤ x ≤ 5; then partial fractions |
| Oct 2021 (Q5, 9) | x = 5 + 2 tan t, y = 8 sec2t | Trigonometric | Gradient −8 at x = 3; Cartesian y = 2(x − 5)2 + 8; range 8 ≤ f(x) ≤ 32 |
| Jun 2021 (Q6, 10) | x = 2 cos 2t, y = 4 sin t | Trigonometric | Area 8√2/3; Cartesian y = √(8 − 4x); range |
| Jan 2021 (Q9, 10) | x = tan θ, y = 2 sin 2θ | Trigonometric | Volume, see Volumes and areas |
| Jan 2021 (Q4, 7) | x = 1/t + 2, y = (1 − 2t)/(3 + t), t > 0 | Rational | Cartesian g(x) = (x − 4)/(3x − 5), x > 2; range of g |
| Oct 2020 (Q4, 12) | x = 2t2 − 6t, y = t3 − 4t | Polynomial | Axis crossings; tangent at B: 7y + 4x − 80 = 0; meets the curve again at x = −40/49 |
- Types: 12 trigonometric, 9 rational or rational-and-polynomial, one each polynomial, roots, logarithmic, and polynomial with trigonometric.
- Cartesian conversions (11 curves): by identity when trigonometric (cos 2t = 1 − 2sin2t in Jun 2021, Jan 2022 and Oct 2024; sec2t = 1 + tan2t in Oct 2021 and Jan 2024; compound angle in Jan 2024), otherwise by making t the subject. Domain or range is asked 8 times, twice with no explicit conversion first (Oct 2022 Q6, Jan 2026 Q5).
- Tangent meets the curve again (Oct 2020, Jun 2022, Jan 2025): substitute x(t), y(t) into the line. The contact point gives a repeated root, so (t − t0)2 is a factor; Jun 2022 turns the same idea into a quadratic in cos t.
- Range traps: the extreme value can sit inside the interval, not at an end (t = 0 in Oct 2021; t = 1 in Jan 2026).
- Parametric areas and volumes are set in 10 of these curves; they are analysed in Volumes and areas.
Connected rates of change
Connected rates appear in 13 of 18 papers (4.1 marks a paper, range 0–8). Spheres and balloons are the most common shape (5 times), and June 2026 Q4 re-ran June 2021 Q3 almost exactly, with a square root added to the volume formula.
| Session (question, marks) | Context | Formula given or built | Rate given | Asked |
|---|---|---|---|---|
| Jun 2026 (Q4, 7) | Container filling | V = (1/3)h2√(h + 4), 0 ≤ h ≤ 21 (given) | dV/dt = 30 | Time to fill (24.5 s); exact dh/dt at h = 5 (108/41), product rule with a root |
| Jan 2026 (Q8a, 3) | Balloon deflating | V = (4/3)πr3 | dV/dt constant | Show dr/dt = −k/r2, which starts a differential equation |
| Jun 2025 (Q2, 4) | Ice ball melting | V = (4/3)πr3 (given) | dV/dt = −k | Show dr/dt is inversely proportional to r2 |
| Jan 2025 (Q4i, 4) | Balloon inflating | V = (4/3)πr3 (given) | dV/dt = 70π | dr/dt at r = 5 |
| Oct 2024 (Q5, 6) | Inverted cone filling | Similar triangles give V = 4πh3/75 (show) | dV/dt = 2π | dh/dt after 1.5 minutes: V = 180π, h = 15, dh/dt = 1/18 |
| Jun 2024 (Q4, 6) | Circle segment, radius 5 | A = (25/2)(θ − sin θ), so dA/dθ = K(1 − cos θ) | dθ/dt = 0.1 | dA/dt at a given θ |
| Jan 2024 (Q4, 5) | Cone, height fixed at 5 | l = √(25 + r2); S = πr2 + πrl (given) | dr/dt = 3 | dS/dt at r = 1.5, to 1 d.p. |
| Oct 2023 (Q2, 7) | Expanding cube | S = 6x2, V = x3 | dS/dt = 4 | Show dx/dt = 1/(3x); show dV/dt = V^(1/3) |
| Jan 2023 (Q7a, d; 4) | Balloon | V = (4/3)πr3 (given) | From the solved differential equation | dV/dr; dr/dt at t = 3, with units |
| Jun 2022 (Q3, 8) | Circle, then cylinder | A = πx2, V = 3πx3 | dA/dt = −0.5 | dx/dt at x = 7 (−1/(28π)); dV/dt at x = 4 (−9) |
| Jan 2022 (Q4, 8) | Icosahedron | A = 5√3x2 (show); V given | dA/dt = 0.025 | Show dV/dA; dV/dt at x = 2, to 2 s.f. |
| Oct 2021 (Q9a, 4) | Cylindrical tank, diameter 8 m | V = 16πh; in 0.6π, out 0.15πh | Net dV/dt | Show dh/dt = (12 − 3h)/320, which is then solved |
| Jun 2021 (Q3, 7) | Bowl filling | V = (1/3)h2(h + 4), 0 ≤ h ≤ 20 (given) | dV/dt = 160 | Time to fill (20 s); dh/dt at h = 5 (96/23) |
- Missing in October 2020, January 2021, October 2022, June 2023 and October 2025. No paper has gone two sessions in a row without one since 2021.
- Shapes: spheres and balloons 5, cones 2, cylinders and circles 2, containers with a given V(h) 2, a cube, an icosahedron and a circle segment once each.
- Formula given vs built: the question supplies the volume or area formula in 7 of the 13. Students build it themselves for the cube, the cylinder pieces, the segment area, the cone (similar triangles) and, in January 2026, the sphere, whose formula was not printed.
- Three rates questions start a differential equation (Oct 2021, Jan 2023, Jan 2026): the chain rule produces dh/dt or dr/dt, which the next part separates and solves.
- Calculus beyond the chain rule: the June 2026 volume needs the product rule on h2√(h + 4); the January 2024 surface area needs the chain rule on √(25 + r2).
Integration by substitution
A substitution integral appears in all 18 papers (6.2 marks a paper, range 3–8), 18 in total. The substitution is printed in 16 of them; only October 2020 and October 2023 left the choice to the student. The real test is usually what comes after the change of variable: partial fractions, parts, a trig identity or a reverse chain rule.
| Session (question, marks) | Integral | Substitution | Type | What the u-integral became |
|---|---|---|---|---|
| Jun 2026 (Q7ii, 7) | ∫2x3/√(1 − 4x2) dx, definite | 2x = sin u | Trig substitution | (1/8)∫sin3u du, using sin3u = sin u(1 − cos2u) |
| Jan 2026 (Q4, 9) | ∫ from 0 to ln 6 of (2ex + 3)/(ex + 4) dx | u = ex + 4 | Exponential | (2u − 5)/(u(u − 4)) on [5, 10]; partial fractions, P ln 2 + Q ln 3 |
| Oct 2025 (Q6, 7) | ∫sin 2θ/√(3 + cos θ) dθ, definite | u = 3 + cos θ | Trig inside | −2(u − 3)/√u on [3, 4]; powers of u, a√3 + b |
| Jun 2025 (Q7, 6) | ∫(tan x + tan3x)/(4 + sec2x)3 dx, indefinite | u = tan x | Trig inside | u/(5 + u2)3; reverse chain rule |
| Jan 2025 (Q7, 6) | ∫1/(16 − x2)^(3/2) dx, definite | x = 4 sin θ | Trig substitution | (1/16)∫sec2θ dθ |
| Oct 2024 (Q6, 5) | ∫9x5/√(x3 + 1) dx, indefinite | u = √(x3 + 1) | Root | 6∫(u2 − 1) du |
| Jun 2024 (Q9, 9) | Volume π∫x^(−1/2)/((1 + x)(arctan √x)2) dx on [1, 3] | tan u = √x | Inverse-trig substitution | 2π∫u−2 du on [π/4, π/3], V = 2 |
| Jan 2024 (Q7, 8) | ∫e^(4x + 2 sin 2x) cos2x dx, then a volume | u = 4x + 2 sin 2x | Trig inside | (1/8)∫eu du, since du/dx = 8cos2x |
| Oct 2023 (Q3ii, 7) | ∫4x/(2x − 1)2 dx, definite | Not given (u = 2x − 1 accepted) | Linear | (u + 1)/u2, giving ln u − 1/u; a + ln b |
| Jun 2023 (Q5ii, 6) | ∫27x/√(1 − 3x) dx, indefinite | u = √(1 − 3x) | Root | −6∫(1 − u2) du; −2(Ax + B)√(1 − 3x) + k |
| Jan 2023 (Q4, 9) | ∫(8x + 4)…e^√(2x + 1) dx, definite | u = √(2x + 1) | Root | ∫ from 3 to 5 of 2u2eu du; parts twice, 34e5 − 10e3 |
| Oct 2022 (Q7i, 7) | ∫ from ln 5 to ln 7 of 4e3x/(ex − 3) dx | u = ex − 3 | Exponential | 4(u + 3)2/u; divide, then 2u2 + 24u + 36 ln u; a + b ln 2 |
| Jun 2022 (Q5, 8) | ∫ from 0 to 1 of (3x + 2)/(4 − x2)^(3/2) dx | x = 2 sin u | Trig substitution | (3/2)sec u tan u + (1/2)sec2u; 7√3/6 − 3/2 |
| Jan 2022 (Q5b, 6) | Parametric area ∫t3/√(81 − 16t2) dt | u = 81 − 16t2 (or otherwise) | Polynomial inside a root | Powers of u |
| Oct 2021 (Q6, 7) | Area ∫16 sin 2x/(3 + 4 sin x)2 dx on [π/6, π/2] | u = 3 + 4 sin x | Trig inside | 2/u − 6/u2 on [5, 7]; ln(49/25) − 12/35 |
| Jun 2021 (Q4, 8) | ∫ from 1 to 4 of 10/(5x + 2x√x) dx | u = √x | Root | 20/(u(5 + 2u)); partial fractions, 4 ln(14/9) |
| Jan 2021 (Q5, 8) | ∫4/(3 + √(2x − 1)) dx, definite | u = 3 + √(2x − 1) | Root | 4(u − 3)/u; divide, p + q ln 2 |
| Oct 2020 (Q7i, 6) | ∫ from 1 to 5 of 3x/√(2x − 1) dx | Not given (u = √(2x − 1) or u = 2x − 1) | Root | Powers of u; 16 |
- Substitution types: roots 6, trig functions inside (u = 3 + 4 sin x and similar) 4, trig substitutions (x = a sin θ, tan u = √x) 4, exponential 2, linear or polynomial 2.
- What follows the change of variable: powers of u 8 times, partial fractions 2, division of a fraction 2, parts 1, trig integrals 3, eu once, a reverse chain rule once.
- Definite 15, indefinite 3 (Jun 2023, Oct 2024, Jun 2025). In definite ones the limits must be changed: the mark schemes award an M mark for using the u-limits, and returning to x is never needed.
- Context: 14 standalone, 2 areas (Oct 2021; Jan 2022, parametric), 2 volumes (Jan 2024, Jun 2024).
- Trig substitutions are rising: x = 2 sin u (Jun 2022), x = 4 sin θ (Jan 2025), 2x = sin u (Jun 2026). Each relies on 1 − sin2θ = cos2θ to clear a root.
- The step the schemes police hardest: converting dx. The June 2021 scheme states that dx cannot simply be replaced by du; doing so loses the method mark for changing the integral.
Integration by parts
Integration by parts appears in every paper: as its own part in 16, and inside a differential equation in the other two (June 2021, October 2025). LIATE gives a correct choice of u in all 19 integrals: u = a logarithm 4 times, u = a power of x 11 times, and the 4 ex-times-trig loops work with either choice.
| Session (question, marks) | Integral | u (LIATE letter) | dv/dx | Applications | Context and result |
|---|---|---|---|---|---|
| Jun 2026 (Q7i, 6) | ∫e^(2x) cos 4x dx | Either; scheme Way One uses u = e^(2x) | cos 4x | Loop | Standalone; (1/5)e^(2x) sin 4x + (1/10)e^(2x) cos 4x + c |
| Jan 2026 (Q2, 5) | ∫ from 2 to 2e2 of x3 ln(x/2) dx | ln(x/2), L | x3 | Once | Standalone, exact value |
| Oct 2025 (Q8a, 5) | ∫12t e^(−t) dt | 12t, A | e^(−t) | Once | Differential equation: V = 18 − 12te^(−t) − 12e^(−t) |
| Jun 2025 (Q9b, 4) | ∫ex cos x dx | Either; scheme shows both ways | cos x or ex | Loop | Volume of a paperweight |
| Jan 2025 (Q5i, 4) | ∫x2e^(4x) dx | x2, A | e^(4x) | Twice | Standalone; (1/4)x2e^(4x) − (1/8)xe^(4x) + (1/32)e^(4x) + c |
| Oct 2024 (Q10b, 5) | ∫12t sin2t cos t dt | t, A | sin2t cos t, so v = (1/3)sin3t | Once, then ∫sin3t by identity | Parametric area, pπ + q |
| Jun 2024 (Q1, 5) | ∫ from 0 to π/6 of x cos 3x dx | x, A | cos 3x | Once | Standalone; π/18 − 1/9 |
| Jan 2024 (Q5a, 4) | ∫x2 cos 2x dx | x2, A | cos 2x | Twice | Then used to solve a differential equation |
| Oct 2023 (Q3i, 5) | ∫x2e^(2x) dx, exact value | x2, A | e^(2x) | Twice | Standalone |
| Jun 2023 (Q5i, 4) | ∫x2ex dx | x2, A | ex | Twice | Standalone; x2ex − 2xex + 2ex + c |
| Jan 2023 (Q4b, 5) | ∫ from 3 to 5 of 2u2eu du | u2, A | eu | Twice | After the substitution u = √(2x + 1); 34e5 − 10e3 |
| Oct 2022 (Q7ii, 5) | ∫3ex cos 2x dx | Either; main scheme uses u = 3ex | cos 2x | Loop | Standalone show-that; (6/5)ex sin 2x + (3/5)ex cos 2x + c |
| Jun 2022 (Q8b, 3) | ∫x2e^(−x) dx | x2, A | e^(−x) | Twice | Volume, then density |
| Jan 2022 (Q7b, 5) | ∫ from 0 to 4 of (x2 − 8x + 16)e^(2x) dx | The quadratic, A | e^(2x) | Twice | Volume of a doorknob |
| Oct 2021 (Q8b, 4) | ∫ from 1 to e of x2(ln x)2 dx | (ln x)2, L | x2 | Once, reusing (a) | Volume; π(5e3 − 2)/27 |
| Oct 2021 (Q8a, 3) | ∫x2 ln x dx | ln x, L | x2 | Once | Feeds (b); (x3/3) ln x − x3/9 + c |
| Jun 2021 (Q8a, part) | ∫6xe^(−2x) dx | 6x, A | e^(−2x) | Once | Differential equation; y^(2/3) = 2 − (2x + 1)e^(−2x) |
| Jan 2021 (Q7a, 5) | ∫e^(2x) sin x dx | sin x, T (scheme Way 1) | e^(2x) | Loop | Then an area; (e^(2π) + 1)/5 |
| Oct 2020 (Q5a, 3) | ∫ln x/x2 dx | ln x, L | x^(−2) | Once | Then an area; 1 + 2 ln 2 |
- LIATE counts: L (logarithm) 4, A (algebraic) 11, loops 4. I (inverse trig) never appears as u. Every choice that LIATE makes is one the mark schemes accept.
- The loop is the one place to choose freely. LIATE says u = trig (T before E); Jan 2021’s scheme does that, Oct 2022’s and Jun 2026’s main methods take u = e^(ax), and Jun 2025’s shows both. What matters is keeping the same choice for the second application; swapping it undoes the first step.
- Applications: once 8, twice 7, loop 4. Every “twice” case is x2 times an exponential or a cosine (or the quadratic in Jan 2022).
- Exponents and arguments seen: ex, e^(2x), e^(4x), e^(−x), e^(−2x), e^(−t); cos 2x, cos 3x, cos 4x, sin x, cos x; ln x, (ln x)2, ln(x/2). The linear coefficient is the main source of slips (v = (1/4)e^(4x), not e^(4x)).
- Context: 7 standalone, 5 inside volumes (4 papers), 3 inside areas, 3 inside differential equations, 1 after a substitution. Integration by parts is the main tool for finishing volume questions.
- ∫ln x dx on its own (u = ln x, dv/dx = 1) has not been set in this period.
- Marking points: M1 for parts “the right way round” to the correct form, dM1 for the second application, A1 for the result, with +c usually required on indefinite answers. The June 2022 scheme explicitly credits the tabular (DI) method, row by row.
Volumes and areas
A volume of revolution appeared in 17 of the 18 papers; June 2026 is the only paper with no volume or area at all. Most volumes are really integration-technique questions in disguise: setting up π∫y2 dx is worth 1–3 marks, and finishing the integral (parts, substitution, partial fractions, a trig identity) carries the rest.
| Session (question, marks) | Curve | Region | Volume or area | How the integral is finished | Result |
|---|---|---|---|---|---|
| Jun 2026 | None | ||||
| Jan 2026 (Q9, 8) | x = 6 sin t, y = 5 sin 2t, 0 ≤ t ≤ π/2 | Curve and x-axis | Parametric volume | 600π∫sin2t cos3t dt; cos3t = cos t(1 − sin2t), reverse chain rule | 80π |
| Oct 2025 (Q9b, 9) | x = ln(2t + 5), y = 1/(t + 1) | ln 9 ≤ x ≤ ln 15 | Parametric area | ∫ from 2 to 5 of 2/((t + 1)(2t + 5)) dt; partial fractions | ln α |
| Oct 2025 (Q2, 5) | Cartesian curve | 2 ≤ x ≤ 8 | Volume | Algebraic integration, exact | Exact |
| Jun 2025 (Q9, 12) | y = cos x + ex/5 | Curve, axes and a vertical line | Volume, then a paperweight made of two solids | Expand y2; cos2x by identity; ∫ex cos x by the parts loop | 2 s.f. |
| Jan 2025 (Q1, 5) | y = 4/(x + 2) | 0 ≤ x ≤ 8 | Volume | 16π∫(x + 2)−2 dx | 32π/5 |
| Oct 2024 (Q10, 8) | x = 3t2, y = sin t sin 2t, 0 ≤ t ≤ π | Curve and x-axis | Parametric area | 12∫t sin2t cos t dt; parts | pπ + q |
| Oct 2024 (Q7b, 6) | y = √((3x − 1)/(x + 2)) | 1 ≤ x ≤ 4 | Volume | Divide: 3 − 7/(x + 2), then a log | π(p + q ln 2) |
| Jun 2024 (Q9, 9) | y2 = x^(−1/2)/((1 + x)(arctan √x)2) | 1 ≤ x ≤ 3 | Volume | tan u = √x gives 2π∫u−2 du | 2 |
| Jun 2024 (Q5b–c, 11) | x = t2 + 2t, y = 2/(t(3 − t)) | Curve and the line y = 1 | Parametric area | 4∫(t + 1)/(t(3 − t)) dt with a rectangle; partial fractions | Exact |
| Jan 2024 (Q7, 8) | An e^(2x + sin 2x) cos x curve | Curve and both axes | Volume | Substitution u = 4x + 2 sin 2x from part (a) | Exact |
| Oct 2023 (Q8d, 6) | x = 6t − 3 sin 2t, y = 2 cos t | Curve and both axes | Parametric volume | 48π∫sin2t cos2t dt = 6π∫(1 − cos 4t) dt | Exact |
| Jun 2023 (Q8d, 7) | x = t + 1/t, y = t − 1/t | Curve, the normal at P and the x-axis | Parametric volume plus a cone | π∫y2(dx/dt) dt, then add a cone | Exact |
| Jan 2023 (Q8b, 6) | x = sin2t, y = 2 tan t | Curve, the normal and the x-axis | Parametric area plus a triangle | ∫4 sin2t dt by identity, then a triangle | Exact |
| Jan 2023 (Q3, 5) | y2 = 3x/(3x2 + 5) | Between two vertical lines | Volume | f′(x)/f(x), giving a log | a ln b, a irrational, b prime |
| Oct 2022 (Q5, 6) | y = 12√x/(2x2 + 3)^1.5 | 1 ≤ x ≤ k | Volume given as 713π/648 | Reverse chain rule: −18(2x2 + 3)−2 | Solve for k |
| Jun 2022 (Q8, 10) | y = 10xe^(−x/2) | 0 ≤ x ≤ 10, doubled | Volume, then density = mass ÷ volume | 100π∫x2e^(−x) dx; parts twice | 3.99 g/cm3 |
| Jan 2022 (Q7, 8) | f(x) = (1/4)(4 − x)ex | 0 ≤ x ≤ 4 | Volume of a doorknob | (π/16)∫(x2 − 8x + 16)e^(2x) dx; parts twice | pπ(e^q + r) |
| Jan 2022 (Q5, 10) | x = √(9 − 4t), y = t3/√(9 + 4t) | Curve and both axes | Parametric area | 2∫t3/√(81 − 16t2) dt; substitution u = 81 − 16t2 | Exact |
| Oct 2021 (Q8b, 4) | y = x ln x | 1 ≤ x ≤ e | Volume | Parts on x2(ln x)2, reusing (a) | π(5e3 − 2)/27 |
| Oct 2021 (Q6, 7) | y = 16 sin 2x/(3 + 4 sin x)2 | π/6 ≤ x ≤ π/2 | Area | Substitution u = 3 + 4 sin x | ln(49/25) − 12/35 |
| Jun 2021 (Q6a, 6) | x = 2 cos 2t, y = 4 sin t | Curve and both axes | Parametric area | 32∫sin2t cos t dt; reverse chain rule | 8√2/3 |
| Jun 2021 (Q2, 7) | y = 9/(2x − 3)^1.25 | Curve, y = 9 and x = 6 | Volume: cylinder minus curve | Power rule on (2x − 3)^(−2.5) | 298π |
| Jan 2021 (Q9, 10) | x = tan θ, y = 2 sin 2θ | 0 ≤ x ≤ √3 | Parametric volume | 8π∫(1 − cos 2θ) dθ | 8π2/3 − 2√3π |
| Jan 2021 (Q7b, 2) | y = e^(2x) sin x | 0 ≤ x ≤ π | Area | From the parts loop in (a) | (e^(2π) + 1)/5 |
| Oct 2020 (Q5b, 4) | y = (3 + 2x − ln x)/x2 | 2 ≤ x ≤ 4 | Area | Parts result from (a) | 1 + 2 ln 2 |
| Oct 2020 (Q3, 6) | y = e^(0.5x) − 2 | Curve and both axes | Volume | Expand y2 | 8π ln 2 − 5π |
- Volumes: 13 Cartesian and 4 parametric (Jan 2021, Jun 2023, Oct 2023, Jan 2026). Areas: 6 parametric and 3 Cartesian.
- Finishing technique for the 17 volumes: parts in 4 (Oct 2021, Jan 2022, Jun 2022, Jun 2025), a trig identity in 3, the reverse chain rule in 2, the power rule in 2, a substitution in 2, and once each a log by division, f′/f, plain expansion and a parametric power integral. October 2025’s is a plain algebraic integral.
- Composite regions (curve plus a cylinder, cone, triangle or rectangle) in Jun 2021, Jan 2023, Jun 2023 and Jun 2024.
- Real objects (Jan 2022 doorknob, Jun 2022 density, Jun 2025 paperweight) add a final step that uses the volume, worth 1–4 marks.
- Working backwards from a given volume to a limit happened once (Oct 2022).
- Parametric volumes always reduce to a product of sin and cos powers, cleared by a double-angle identity or by writing an odd power as one factor times (1 − sin2) or (1 − cos2).
Differential equations
Every paper has a separable differential equation: 19 in all (October 2021 has two), worth 8.4 marks a paper on average (range 5–12). 13 of the 19 are set in context, and since January 2024 the integration on one side has often needed a P4 technique: partial fractions, parts or a trig result.
| Session (question, marks) | Equation and condition | Integration needed | Context | Asked after solving |
|---|---|---|---|---|
| Jun 2026 (Q8, 10) | dS/dt = (128 − S)/50, S = 18 at t = 0 (after a non-DE first model) | ∫dS/(128 − S), a log | Algae on a pond | S = 128 − 110e^(−t/50); maximum area 128 m2 |
| Jan 2026 (Q8, 10) | dr/dt = −k/r2, built from a constant rate of volume loss | ∫r2 dr | Deflating balloon | r(t) from r = 30 at t = 0 and r = 12 at t = 24; time until V = 0, to 1 d.p. |
| Oct 2025 (Q8, 6) | dV/dt = 12te^(−t), V = 6 at t = 0 | Parts on the t side | Water container | V = 18 − 12te^(−t) − 12e^(−t); never full, since V → 18 < 20 |
| Jun 2025 (Q3, 6) | dy/dx = 3 sin 2x/(y cos22x), y = 4 at x = π/6 | ∫3 sec 2x tan 2x dx | None | y2 = 3 sec 2x + 10 |
| Jan 2025 (Q4ii, 6) | dh/dt = k/h3, h = 4 at t = 0 and 6 at t = 5 | ∫h3 dh | Water depth in a cave | k = 52; T when h = 10, to 1 d.p. |
| Oct 2024 (Q9, 10) | dh/dt proportional to h(2h − 1) cos(t/10), h = 2.5 at t = 0 | Partial fractions on the h side | Fairground ride | h in a given exponential form; time of the third maximum, nearest second |
| Jun 2024 (Q7, 11) | dx/dt = k − 3x, x = 0 at t = 0 | ∫dx/(k − 3x), a log | Current in a circuit | Long-term 7 A gives k = 21; time to reach 5 A, 2 s.f. |
| Jan 2024 (Q5b, 5) | dy/dt = t2cos2t/y2 | ∫t2cos2t dt via cos2t = (1 + cos 2t)/2 and part (a) | None | y3 = f(t) |
| Oct 2023 (Q7, 12) | dx/dt = x(9 − 2x)/3, x = 3 at t = 0 (after a non-DE first model) | Partial fractions | Goats on an island | x = 9/(2 + e^(−3t)); long-term populations from both models |
| Jun 2023 (Q6, 9) | dθ/dt = −k(θ − 15), θ = 85 at t = 0 and 40 at t = 10 | ∫dθ/(θ − 15), a log | Engine cooling | θ as an exponential; time to reach 20 °C, nearest minute |
| Jan 2023 (Q7b–c, 8) | dV/dt = 900/(2t + 3)2, V = 0 at t = 0 | Direct, a power of (2t + 3) | Balloon | V = 300t/(2t + 3); upper limit 150; radius at t = 3 |
| Oct 2022 (Q10, 8) | dr/dt = −k/r2, from “inversely proportional to the square of the radius” | ∫r2 dr | Melting ice ball | r = 12 to 6 in 15 minutes; time to melt; sketch r against t |
| Jun 2022 (Q2b, 6) | cot y dy/dx = 1/((1 + 3x)(1 − x)), y = π/2 at x = 1/2 | ∫cot y dy = ln sin y; partial fractions on the x side | None | sin4y = (1 + 3x)/(5(1 − x)) |
| Jan 2022 (Q9b–c, 9) | 3 cosec 2x · dy/dx = y(1 + 2 ln y)3 | ∫dy/(y(1 + 2 ln y)3), signposted by part (a)’s derivative | None | General, then particular solution in exponential form |
| Oct 2021 (Q9b, 6) | dh/dt = (12 − 3h)/320, h = 0.5 at t = 0 | ∫dh/(12 − 3h), a log | Cylindrical tank | Time to reach 3.5 m: (320/3) ln 7 ≈ 208 minutes |
| Oct 2021 (Q2, 6) | dy/dx = 4y2/√(4x + 5), y = 1/3 at x = −1/4 | ∫y−2 dy and ∫4(4x + 5)^(−1/2) dx | None | y = 1/(7 − 2√(4x + 5)) |
| Jun 2021 (Q8, 9) | dy/dx = 6xe^(−2x) y^(1/3), y = 1 at x = 0 | Parts on the x side | None | y^(2/3) = 2 − (2x + 1)e^(−2x); horizontal asymptote y = 2√2 |
| Jan 2021 (Q10b–d, 11) | dH/dt = −(H − 5)(H + 3)/40, H = 13 at t = 0 | Partial fractions | Storage tank | H = (10 + 3e^(−0.2t))/(2 − e^(−0.2t)); time to 8 m; long-term depth 5 m |
| Oct 2020 (Q9, 9) | dA/dt = A^(3/2)/(5t2), A = 2.25 at t = 3 | Powers | Bacteria on a dish | A = (30t/(19t + 3))2; limiting area 900/361 ≈ 2.49 cm2 |
- Integration on the variable side: a log of a linear expression 4 times, powers 8, partial fractions 3, cot y once, a signposted composite once, and 2 direct integrations (Jan 2023, Oct 2025). On the independent side: parts 3 (Jun 2021, Jan 2024, Oct 2025), partial fractions once (Jun 2022), trig 3 (Jun 2025, Jan 2024, Oct 2024).
- Context vs pure: 13 in context, 6 pure (Jun 2021, Oct 2021 Q2, Jan 2022, Jun 2022, Jan 2024, Jun 2025).
- Built from words three times: “inversely proportional to r2” (Oct 2022), rates in and out of a tank (Oct 2021), a constant rate of volume loss (Jan 2026).
- Follow-ups: a long-term or limiting value 8 times; a time 8 times; one sketch (Oct 2022). Two papers (Oct 2023, Jun 2026) open with a non-DE model to compare against.
- Where marks are lost (from the scheme notes): one constant of integration, found from the starting values before rearranging; logs combined before exponentiating; and the final “in context” answer with units and the stated accuracy.
Vectors
Vectors are the largest topic: every paper, 10.7 marks on average (range 8–16), across 24 questions. Almost every part is one of five routines: where two lines meet, an angle by the scalar product, the foot of a perpendicular, an area, or a reflection. Six papers split vectors over two questions.
| Session (question, marks) | Set-up | Tasks |
|---|---|---|
| Jun 2026 (Q5, 9) | Triangle ABC from AB and AC | Angle BAC (1 d.p.); area of ABC (1 d.p.); D on AB extended with angle ADC = 90° |
| Jun 2026 (Q2, 6) | Two lines | Explain why they are not parallel; prove by contradiction that they do not meet |
| Jan 2026 (Q6, 10) | l1, and l2 with an unknown a | Point P on l1 nearest O; a so the lines meet; their intersection Q |
| Oct 2025 (Q7, 6) | Parallelogram from AB and BC | Exact cos θ; area in the form 5√k |
| Oct 2025 (Q5, 6) | l1, and l2 with an unknown β | β so the lines meet; the intersection P |
| Jun 2025 (Q6, 8) | A, B and C(3, α, 5) | Line AB; exact values of α for which angle BAC = 45° (a quadratic) |
| Jan 2025 (Q8, 12) | Line l; A(−2, a, 4) and B(b, 3, 1) on it; C | a and b; AB; angle CAB (1 d.p.); both positions of D on l with area CAD = 2 × area CAB |
| Oct 2024 (Q8, 10) | A and B; l2 with unknowns p, q | Line AB; p and q so the lines meet at B; exact cos θ; exact length AC with AC ⊥ l2 |
| Jun 2024 (Q6, 10) | l1 and a point A with |OA| = 5√10 | Show 81λ2 + 52λ − 220 = 0; both positions of A; area of OAB (1 d.p.) using l2 through O |
| Jun 2024 (Q2, 6) | OA, AB, and OC with an unknown a | Coordinates of B; values of a with OC ⊥ BC |
| Jan 2024 (Q6, 14) | l1 with an unknown p, and l2 | p so they meet; the intersection; acute angle (1 d.p.); B on l2 with AB ⊥ l2 |
| Oct 2023 (Q6, 10) | l1 and l2 meeting at P | P; cos θ as a fraction; area of isosceles triangle QPR; both positions of R |
| Jun 2023 (Q4, 10) | A, B and P | Line AB; C on l with PC ⊥ l; reflection P′; |PP′| = 4√17 |
| Jan 2023 (Q6, 8) | A, B and C | AB and line l; P on l with CP ⊥ l |
| Oct 2022 (Q9, 5) | Two lines | Prove they are skew |
| Oct 2022 (Q3, 5) | Triangle PQR from PQ and PR | RQ; angle PQR (3 s.f.) |
| Jun 2022 (Q6, 9) | A, B, and C with an unknown p | Line AB; AC ⊥ AB gives p = −8; area of ABC = 9√10 |
| Jan 2022 (Q8, 11) | A and B; l2; C on l2 | Line AB; show the lines do not meet; acute angle between AC and l2 (1 d.p.) |
| Oct 2021 (Q7, 9) | Line l and point A | Foot X; shortest distance √67; reflection B of A in l |
| Jun 2021 (Q9i, 3) | A, B, C collinear with AB : AC = 1 : 3 | Show c = 3b − 2a |
| Jun 2021 (Q7, 10) | Line l | Unit vector OA parallel to l; point X on l closest to O, (7, −4, −6); area of OXA = √101/2 |
| Jan 2021 (Q8, 6) | Two lines with an unknown b | Prove they are skew for every b ≠ 7 |
| Jan 2021 (Q2, 5) | Parallelogram from AB and BC | Angle ABC (2 d.p.); area (1 d.p.) |
| Oct 2020 (Q8, 10) | l1 and l2 | Intersection X, −8i + 5j + 6k; Q on l2 with PQ ⊥ l2, (10/7, 2/7, −57/7) |
- Routine counts: an angle by the scalar product 10 times; the foot of a perpendicular (nearest point, shortest distance) 9; an area of a triangle or parallelogram 8; lines meeting, including finding a constant so they do, 6; proving lines skew or non-intersecting 4; a reflection 2.
- Unknown constants in a line or point (a, b, p, q, α, β) appear in 9 questions. Each is found from one condition: the lines meet, two vectors are perpendicular, or an angle is given.
- Two-answer parts (both positions of a point, or two values of a constant) appear 5 times, all since October 2023 (Oct 2023, Jun 2024 twice, Jan 2025, Jun 2025). They come from a quadratic in λ or from a ratio either side of a point.
- Accuracy demands are shifting to exact forms: exact cos θ in Oct 2023, Oct 2024 and Oct 2025, and exact surd lengths or areas in Jun 2022, Jun 2023, Oct 2024 and Oct 2025. Degrees to 1 d.p. remain common.
- Notation is marked: the October 2020 scheme rejects coordinates where a position vector is asked for, and penalises the wrong notation once.
- Proof meets vectors in June 2026 Q2, where “the lines do not intersect” had to be written as a proof by contradiction.
Proof by contradiction
Proof by contradiction is in every paper (4.6 marks on average, range 2–8). Five families account for all 18; until mid-2023 they were almost all number theory, but since October 2023 five of nine have been tied to another topic: calculus, curves, trigonometry or vectors.
| Session (question, marks) | Statement | Family | The step that produces the contradiction |
|---|---|---|---|
| Jun 2026 (Q2b, 5) | Two given 3D lines do not intersect | Never meets | Solve two components for λ and μ; the third component fails |
| Jan 2026 (Q3, 5) | No positive integers satisfy x2 − 4y2 = 27 (after factorising) | No integer solutions | (x − 2y)(x + 2y) = 27; the pairs 1 × 27 and 3 × 9 give y = 6.5 and 1.5 |
| Oct 2025 (Q10, 6) | Complete: if x2 is odd, x is odd. Then: no integers with a2 − 4b = 27 | Parity | a is odd, a = 2m + 1, so 4(m2 + m − b) = 26, impossible |
| Jun 2025 (Q10, 4) | cos 2x/(cos x − sin x) < 1 for 90° < x < 180° | Inequality | Leads to sin 2x ≥ 0, false for 180° < 2x < 360° |
| Jan 2025 (Q6, 4) | If n2 − 4n + 5 is even, then n is odd | Parity | n = 2m makes n2 − 4n + 5 odd |
| Oct 2024 (Q2, 4) | y = x4 + 10x2 + 8 and y = 2x2 − 7 do not meet | Never meets | x4 + 8x2 + 15 = 0 gives x2 = −3 or −5 |
| Jun 2024 (Q8b, 4) | A line and a curve from the binomial expansion in (a) do not meet | Never meets | The difference is 8(x − 1)2 + x3/24 > 0 on the interval |
| Jan 2024 (Q8, 4) | y = 2x + x3 + cos x has no stationary points | Never meets (no real solution) | 3x2 + 2 − sin x = 0 is impossible, since 3x2 ≥ 0 and 2 − sin x ≥ 1 |
| Oct 2023 (Q4, 5) | k + 9/k ≥ 6 for all positive k; not true for all real k | Inequality | (k − 3)2 < 0 is impossible; a negative k is the counter-example |
| Jun 2023 (Q7, 4) | √7 is irrational (lemma on multiples of 7 given) | Irrational root | p2 = 7q2 forces a common factor 7 |
| Jan 2023 (Q9, 8) | Complete: if p3 is a multiple of 3, so is p. Then: ∛3 is irrational | Irrational root | Both cases 3k + 1 and 3k + 2; then p3 = 3q3 |
| Oct 2022 (Q8, 4) | No positive integers satisfy 3x2 + 2xy − y2 = 25 (started for the student) | No integer solutions | (3x − y)(x + y) = 25; the pairs 5 × 5 and 25 × 1 fail |
| Jun 2022 (Q9, 4) | n2 − 2 is never divisible by 4 | Parity and divisibility | n2 = 4k + 2 makes n even, then n2 − 2 = 2(2m2 − 1) |
| Jan 2022 (Q6, 5) | k, 1 + 2k, 3 + 3k is not a geometric sequence | Never meets (no real solution) | (1 + 2k)2 = k(3 + 3k) gives k2 + k + 1 = 0, discriminant −3 |
| Oct 2021 (Q10, 6) | Complete: if n3 is even, n is even. Then: ∛2 is irrational | Irrational root | p3 = 2q3 makes p and q both even |
| Jun 2021 (Q9ii, 5) | If n2 is a multiple of 3, so is n | Divisibility | n = 3p + 1 and n = 3p + 2, both cases |
| Jan 2021 (Q3, 2) | There is no greatest odd integer | Parity | If N is the greatest, N + 2 is odd and greater |
| Oct 2020 (Q1, 4) | If n3 is even, n is even | Parity | (2p + 1)3 = 2(4p3 + 6p2 + 3p) + 1 is odd |
- Families: parity and divisibility 6, never meets or no real solution 5, irrational roots 3, no integer solutions 2, inequalities 2. Families repeat in runs of up to three (parity from Oct 2020 to Jun 2021; never-meets from Jan 2024 to Oct 2024), so there is no reliable rotation.
- The assumption line is a mark on its own (B1) in every scheme checked. It must negate the statement precisely: “there exists n such that n3 is even and n is odd”, not “for all n”.
- Scaffolded “complete the proof” questions appear 4 times (Oct 2021, Oct 2022, Jan 2023, Oct 2025). Three of them pair a lemma with an application in the second part.
- Cross-topic proofs since October 2023: a derivative (Jan 2024), a binomial expansion (Jun 2024), two curves (Oct 2024), trigonometry (Jun 2025) and vectors (Jun 2026).
- Two-case arguments (3k + 1 and 3k + 2) are required in Jun 2021 and Jan 2023; missing a case caps the marks.
Trends from 2020 to 2026
The topic mix has been stable for six years; what has changed is how each topic is asked. Recent papers demand more unaided algebra, more exact forms and more “find the condition” reasoning.
| What changed | Earlier papers | Recent papers |
|---|---|---|
| No-calculator notices per paper | 1.85 a paper (Oct 2020 to Oct 2024, 13 papers) | 3.6 a paper (Jan 2025 to Jun 2026, 5 papers) |
| Binomial bracket not starting with 1 | 1 of 5 papers (Oct 2020 to Jan 2022) | 11 of 13 papers (Jun 2022 to Jun 2026) |
| Binomial validity range asked | 0 of the first 6 papers | 7 of the last 12, including 4 of the last 5 |
| Implicit follow-up is a gradient condition | 1 of the first 5 papers | 7 of the last 13 |
| Parametric curve type | Trigonometric in 10 of 18 curves to Oct 2024 | Rational in 4 of 6 curves since Jun 2025 |
| Proof by contradiction | Number theory in 8 of 9 (Oct 2020 to Jun 2023) | Tied to another topic in 5 of 9 (Oct 2023 to Jun 2026) |
| Trig substitution (x = a sin θ) | Once in 13 papers (Jun 2022) | Twice in the last 5 (Jan 2025, Jun 2026) |
| Vectors: exact cos θ or two-answer parts | Neither before Oct 2023 | Exact cos θ 3 times and two-answer parts 5 times since Oct 2023 |
| Pure (no-context) differential equations | 4 of the first 7 | 2 of the last 12 |
| Volume of revolution | Every paper, Oct 2020 to Jan 2026 | None in Jun 2026, the first gap |
- What has not changed: every topic scores in nearly every paper, binomial usually opens, vectors stay the largest topic, and question count stays between 8 and 11.
- Implication for teaching: method fluency without a calculator, exact-form answers, and the “condition, then substitute back” pattern now carry more marks than they did in 2021.
October 2026 predictions
The single strongest prediction is a volume of revolution: it appeared in 17 consecutive papers before June 2026 had none. These are patterns, not leaks; Pearson does not rotate P4 topics on a fixed cycle, and every paper covers almost the whole specification.
| Rank | Prediction | Evidence from the 18 papers | Confidence |
|---|---|---|---|
| 1 | A volume of revolution, finished by parts, a substitution, partial fractions or a trig identity; about a 1 in 4 chance it is parametric | 17 of 18 papers; June 2026 was the first without one; 4 of the 17 were parametric | Very high |
| 2 | Implicit differentiation followed by a gradient condition (stationary point, vertical tangent or given gradient), then substitution back into the curve; possibly an a^x term | Every paper; the condition form in 7 of the last 13; a^x three times since June 2023 | Very high (topic), high (condition form) |
| 3 | A parametric curve: dy/dx, a tangent or normal, then a Cartesian form with domain or range, most likely a rational parametrisation | Every paper; tangent or normal in 12 of 18; Cartesian in 11; rational in 4 of the 6 curves since June 2025 | Very high (topic), moderate (rational) |
| 4 | Binomial expansion as Question 1, with a bracket not starting with 1 and a validity range | Question 1 in 11 of 18; a ≠ 1 in 11 of the last 13; validity in 4 of the last 5; October 2023 and October 2025 nearly identical | Very high |
| 5 | Vectors worth 8–16 marks: an unknown constant so lines meet, an angle (possibly exact cos θ), the foot of a perpendicular and an area, perhaps with a two-answer part | Every paper; the five routines cover almost every part; exact cos θ in all three Octobers since 2023 | Very high |
| 6 | A differential equation in context: separate, integrate (log, partial fractions or parts), find c, then a time or a long-term value | Every paper; 13 of 19 in context; a long-term value 8 times and a time 8 times | Very high |
| 7 | A substitution integral with the substitution printed, definite, with the limits to change; a trig substitution is possible | Every paper; printed in 16 of 18; x = a sin θ twice in the last 5 papers | Very high (topic), moderate (trig form) |
| 8 | Integration by parts on x2 times an exponential or cosine (twice), or with u = ln x | Every paper; x2 twice-through 7 times; u = ln x 4 times; the ex-trig loop was just used in June 2026 | Very high (topic), moderate (form) |
| 9 | Partial fractions feeding an integral or a differential equation; an improper fraction is a real possibility in an October paper | 17 of 18 papers; all three improper cases were October papers (2020, 2021, 2024) | Very high (topic), moderate (improper) |
| 10 | Connected rates of change, most likely a sphere, a cone or a container with V(h), possibly leading into a differential equation | 13 of 18; never absent from two sessions running since 2021 | High |
| 11 | Proof by contradiction, 4–6 marks; the family is the least predictable item on the paper | Every paper; irrational roots have not appeared since June 2023, the longest gap of any family; never-meets was just used in June 2026 | Very high (topic), low (family) |
- A likely paper shape: 9 or 10 questions, opening with binomial (6–9 marks), with implicit (8–10), partial fractions or substitution (6–8 each), parametric (9–12), vectors (8–12), a differential equation (6–10), a volume (6–9), rates (4–7) and proof (4–6).
- Less likely, but not to be skipped: a Cartesian area under a curve (3 times, last in October 2021), reflection of a point in a line (twice, last in June 2023), log differentiation of x^(f(x)) (once, October 2020).
- Exam technique that the recent papers reward: full algebraic working on no-calculator questions (3–4 a paper now), exact forms, and the final substitution step in condition questions.
Appendix: every question
All 166 questions with their marks, topic tags and a one-line summary, newest session first.
January 2024 to June 2026
| Session | Q | Marks | Topic | What it asks |
|---|---|---|---|---|
| Jun 2026 | 1 | 9 | Partial fractions + binomial | (2 + 11x)/((1 + x)(2 + 5x)) into partial fractions, expand to x2, validity |
| Jun 2026 | 2 | 6 | Vectors + proof | Lines not parallel; prove by contradiction that they do not meet |
| Jun 2026 | 3 | 11 | Parametric | x = 4/(t + 2), y = 6t/(t + 4): tangent at t = 2; Cartesian form; range |
| Jun 2026 | 4 | 7 | Rates | Container V = (1/3)h2√(h + 4): time to fill; dh/dt at h = 5 |
| Jun 2026 | 5 | 9 | Vectors | Angle BAC; area of ABC; D on AB extended with angle ADC = 90° |
| Jun 2026 | 6 | 10 | Implicit | 4xy2 + 12y + 6x = 53: dy/dx; maximum value of x |
| Jun 2026 | 7 | 13 | Parts + substitution | ∫e^(2x) cos 4x dx (loop); ∫2x3/√(1 − 4x2) dx with 2x = sin u |
| Jun 2026 | 8 | 10 | Differential equation | Algae: a non-DE model, then dS/dt = (128 − S)/50; maximum area |
| Jan 2026 | 1 | 8 | Binomial | (1 + ax)^n from given coefficients: a, n and p; validity |
| Jan 2026 | 2 | 5 | Parts | ∫ from 2 to 2e2 of x3 ln(x/2) dx |
| Jan 2026 | 3 | 5 | Proof | Factorise x2 − 4y2; no positive integers with x2 − 4y2 = 27 |
| Jan 2026 | 4 | 9 | Substitution + partial fractions | u = ex + 4 on ∫(2ex + 3)/(ex + 4) dx from 0 to ln 6 |
| Jan 2026 | 5 | 11 | Parametric | x = (4t − 5)/(2t + 1), y = 2t2 − 4t + 4: point, dy/dx, tangent, domain and range |
| Jan 2026 | 6 | 10 | Vectors | Point on l1 nearest O; constant so the lines meet; intersection |
| Jan 2026 | 7 | 9 | Implicit | x2 tan y + 32y2/π2 = 11: gradient at P; tangent gradient × normal gradient |
| Jan 2026 | 8 | 10 | Rates + differential equation | Deflating balloon: dr/dt = −k/r2; r(t); time until V = 0 |
| Jan 2026 | 9 | 8 | Volume (parametric) | x = 6 sin t, y = 5 sin 2t rotated: 80π |
| Oct 2025 | 1 | 7 | Binomial | (2 + 5x)^−2 to x3; validity; a related quadratic approximation |
| Oct 2025 | 2 | 5 | Volume | Cartesian curve between x = 2 and x = 8 |
| Oct 2025 | 3 | 7 | Parametric | x = (t + 15)/(t + 4), y = 5/(t + 2): Cartesian form; range |
| Oct 2025 | 4 | 10 | Implicit | 4x2 + y2 − 2xy = 24x: gradient 2 at P(a, b) |
| Oct 2025 | 5 | 6 | Vectors | Constant β so the lines meet; intersection |
| Oct 2025 | 6 | 7 | Substitution | u = 3 + cos θ on ∫sin 2θ/√(3 + cos θ) dθ |
| Oct 2025 | 7 | 6 | Vectors | Parallelogram: exact cos θ; area 5√k |
| Oct 2025 | 8 | 6 | Differential equation | dV/dt = 12te^(−t) by parts; will the container ever fill? |
| Oct 2025 | 9 | 15 | Parametric + area | x = ln(2t + 5), y = 1/(t + 1): gradient −4; area by partial fractions |
| Oct 2025 | 10 | 6 | Proof | Odd squares; no integers with a2 − 4b = 27 |
| Jun 2025 | 1 | 8 | Implicit | 2y2 − 6xy = 7e^(2x − 1) + 13: tangent at P |
| Jun 2025 | 2 | 4 | Rates | Melting ice ball: dr/dt inversely proportional to r2 |
| Jun 2025 | 3 | 6 | Differential equation | dy/dx = 3 sin 2x/(y cos22x): y2 = 3 sec 2x + 10 |
| Jun 2025 | 4 | 8 | Partial fractions | Three linear factors; ∫ from 2 to 4 = 5 ln 2 + 4 ln(3/5) |
| Jun 2025 | 5 | 9 | Parametric | x = (3 + 2t)/(1 − t), y = 1 − t2: normal; Cartesian form |
| Jun 2025 | 6 | 8 | Vectors | Line AB; α with angle BAC = 45° |
| Jun 2025 | 7 | 6 | Substitution | u = tan x; reverse chain rule |
| Jun 2025 | 8 | 10 | Binomial | (4 ± x)^(−1/2); product; approximation to √135 |
| Jun 2025 | 9 | 12 | Volume + parts | y = cos x + ex/5; ∫ex cos x dx; paperweight volume |
| Jun 2025 | 10 | 4 | Proof | cos 2x/(cos x − sin x) < 1 for 90° < x < 180° |
| Jan 2025 | 1 | 5 | Volume | y = 4/(x + 2), 0 ≤ x ≤ 8: 32π/5 |
| Jan 2025 | 2 | 8 | Implicit | 3x + 5y2 + 4x2y = 10(2^x) + 35: gradient at P on the y-axis |
| Jan 2025 | 3 | 8 | Binomial | 6(4 + Ax)^(−1/2): A, B and C; validity; x3 coefficient |
| Jan 2025 | 4 | 10 | Rates + differential equation | Balloon dr/dt at r = 5; dh/dt = k/h3, find T |
| Jan 2025 | 5 | 10 | Parts + partial fractions | ∫x2e^(4x) dx; ∫(2x + 11)/((2x + 1)(2 − x)) dx = ln k |
| Jan 2025 | 6 | 4 | Proof | If n2 − 4n + 5 is even then n is odd |
| Jan 2025 | 7 | 6 | Substitution | x = 4 sin θ on ∫1/(16 − x2)^(3/2) dx |
| Jan 2025 | 8 | 12 | Vectors | a and b; AB; angle CAB; two positions of D by area |
| Jan 2025 | 9 | 12 | Parametric | x = 2 cos 2t, y = sin3t: tangent; where it meets the curve again |
| Oct 2024 | 1 | 6 | Binomial | (8 − 3x)^(−1/3); rational approximation to ∛6 |
| Oct 2024 | 2 | 4 | Proof | x4 + 10x2 + 8 and 2x2 − 7 never meet |
| Oct 2024 | 3 | 9 | Parametric | x = 3 sin3θ, y = 1 + cos 2θ: dy/dx; tangent; Cartesian |
| Oct 2024 | 4 | 9 | Implicit | 3x2 + 2y2 − 4xy + 8^x − 11 = 0: normal meets the x-axis |
| Oct 2024 | 5 | 6 | Rates | Inverted cone V = 4πh3/75; dh/dt after 1.5 minutes |
| Oct 2024 | 6 | 5 | Substitution | u = √(x3 + 1) on ∫9x5/√(x3 + 1) dx |
| Oct 2024 | 7 | 8 | Partial fractions + volume | (3x − 1)/(x + 2) = 3 − 7/(x + 2); volume π(p + q ln 2) |
| Oct 2024 | 8 | 10 | Vectors | Line AB; p and q so the lines meet at B; exact cos θ; length AC |
| Oct 2024 | 9 | 10 | Partial fractions + differential equation | Fairground ride; time of the third maximum |
| Oct 2024 | 10 | 8 | Area (parametric) + parts | x = 3t2, y = sin t sin 2t: area pπ + q |
| Jun 2024 | 1 | 5 | Parts | ∫ from 0 to π/6 of x cos 3x dx |
| Jun 2024 | 2 | 6 | Vectors | Coordinates of B; a with OC ⊥ BC |
| Jun 2024 | 3 | 7 | Implicit | 8x3 − 3y2 + 2xy = 9: normal at (2, 5) |
| Jun 2024 | 4 | 6 | Rates | Circle segment: dA/dθ = K(1 − cos θ); dA/dt |
| Jun 2024 | 5 | 13 | Parametric + area + partial fractions | x = t2 + 2t, y = 2/(t(3 − t)): end points; area with y = 1 |
| Jun 2024 | 6 | 10 | Vectors | |OA| = 5√10: quadratic in λ; area of OAB |
| Jun 2024 | 7 | 11 | Differential equation | Current: dx/dt = k − 3x; k from the long-term value; time to 5 A |
| Jun 2024 | 8 | 8 | Binomial + proof | (8 − 3x)^(4/3); a line and a curve do not meet |
| Jun 2024 | 9 | 9 | Substitution + volume | tan u = √x; volume 2 |
| Jan 2024 | 1 | 4 | Binomial | (1 − 4x)^−3 to x3 |
| Jan 2024 | 2 | 10 | Partial fractions | Repeated factor; ∫ = p ln q + r |
| Jan 2024 | 3 | 9 | Implicit | y2x + 3y = 4x2 + k: minimum point P(p, 2) |
| Jan 2024 | 4 | 5 | Rates | Cone of fixed height: dS/dt at r = 1.5 |
| Jan 2024 | 5 | 9 | Parts + differential equation | ∫x2 cos 2x dx; dy/dt = t2cos2t/y2 |
| Jan 2024 | 6 | 14 | Vectors | p so the lines meet; intersection; acute angle; foot B |
| Jan 2024 | 7 | 8 | Substitution + volume | u = 4x + 2 sin 2x; volume |
| Jan 2024 | 8 | 4 | Proof | y = 2x + x3 + cos x has no stationary points |
| Jan 2024 | 9 | 12 | Parametric | x = sec t, y = √3 tan(t + π/3): dy/dx; tangent; Cartesian |
October 2020 to October 2023
| Session | Q | Marks | Topic | What it asks |
|---|---|---|---|---|
| Oct 2023 | 1 | 5 | Binomial | (2 − 5x)^−2; validity |
| Oct 2023 | 2 | 7 | Rates | Cube: dx/dt = 1/(3x); dV/dt = V^(1/3) |
| Oct 2023 | 3 | 12 | Parts + substitution | ∫x2e^(2x) dx exactly; ∫4x/(2x − 1)2 dx with the student’s own substitution |
| Oct 2023 | 4 | 5 | Proof | k + 9/k ≥ 6 for k > 0; not true for all real k |
| Oct 2023 | 5 | 10 | Implicit | y3 − x2 + 4x2y = k: the normal y = x gives k = 36 |
| Oct 2023 | 6 | 10 | Vectors | Intersection P; cos θ; isosceles triangle area; positions of R |
| Oct 2023 | 7 | 12 | Partial fractions + differential equation | Goats: a non-DE model, then dx/dt = x(9 − 2x)/3 |
| Oct 2023 | 8 | 14 | Parametric + volume | x = 6t − 3 sin 2t, y = 2 cos t: dy/dx; tangent; volume |
| Jun 2023 | 1 | 9 | Binomial | (1/4 − x/2)^(−3/2); a related expansion |
| Jun 2023 | 2 | 10 | Implicit | 2^x − 4xy + y2 = 13: tangent meets the x-axis |
| Jun 2023 | 3 | 11 | Partial fractions | (8x − 5)/((2x − 1)(4x − 3)); integral; find k |
| Jun 2023 | 4 | 10 | Vectors | Line AB; foot C; reflection P′; |PP′| |
| Jun 2023 | 5 | 10 | Parts + substitution | ∫x2ex dx; u = √(1 − 3x) on ∫27x/√(1 − 3x) dx |
| Jun 2023 | 6 | 9 | Differential equation | Engine cooling dθ/dt = −k(θ − 15); time to 20 °C |
| Jun 2023 | 7 | 4 | Proof | √7 is irrational |
| Jun 2023 | 8 | 12 | Parametric + volume | x = t + 1/t, y = t − 1/t: normal; volume with a cone |
| Jan 2023 | 1 | 9 | Partial fractions + binomial | (5x + 10)/((1 − x)(2 + 3x)); expand; validity |
| Jan 2023 | 2 | 6 | Parametric | Points lie on a straight line; meet y = x + 12 |
| Jan 2023 | 3 | 5 | Volume | y2 = 3x/(3x2 + 5): a ln b |
| Jan 2023 | 4 | 9 | Substitution + parts | u = √(2x + 1); ∫2u2eu du = 34e5 − 10e3 |
| Jan 2023 | 5 | 7 | Implicit | y2 = 2x2 + 15x + 10y: interval where the curve is undefined |
| Jan 2023 | 6 | 8 | Vectors | Line AB; foot P from C |
| Jan 2023 | 7 | 12 | Differential equation + rates | Balloon: V = 300t/(2t + 3); limit; r and dr/dt at t = 3 |
| Jan 2023 | 8 | 11 | Parametric + area | x = sin2t, y = 2 tan t: normal; area of S |
| Jan 2023 | 9 | 8 | Proof | Complete the p3 proof; ∛3 is irrational |
| Oct 2022 | 1 | 3 | Parametric | x = t/(t − 3), y = 1/t + 2: Cartesian form |
| Oct 2022 | 2 | 7 | Partial fractions | 3x/((2x − 1)(x − 2)); ∫ = ln k |
| Oct 2022 | 3 | 5 | Vectors | RQ; angle PQR |
| Oct 2022 | 4 | 8 | Binomial | (4 − x2)^(−1/2); validity; √3 approximation |
| Oct 2022 | 5 | 6 | Volume | y = 12√x/(2x2 + 3)^1.5; find k from V = 713π/648 |
| Oct 2022 | 6 | 8 | Parametric | x = 1 + 3 tan t, y = 2 cos 2t: tangent; k; range |
| Oct 2022 | 7 | 12 | Substitution + parts | u = ex − 3 gives a + b ln 2; ∫3ex cos 2x dx (loop) |
| Oct 2022 | 8 | 4 | Proof | No positive integers with 3x2 + 2xy − y2 = 25 |
| Oct 2022 | 9 | 5 | Vectors | Prove the lines are skew |
| Oct 2022 | 10 | 8 | Differential equation | Melting ice ball dr/dt = −k/r2; time to melt; sketch |
| Oct 2022 | 11 | 9 | Implicit | (x + y)3 + 10y2 = 108x: furthest point south |
| Jun 2022 | 1 | 7 | Binomial | (3 + kx)^−2: k = −6; x3 coefficient |
| Jun 2022 | 2 | 9 | Partial fractions + differential equation | cot y dy/dx = 1/((1 + 3x)(1 − x)) |
| Jun 2022 | 3 | 8 | Rates | Circle area decreasing; cylinder volume |
| Jun 2022 | 4 | 8 | Implicit | 16x3 − 9kx2y + 8y3 = 875: stationary point, k = 4/3 |
| Jun 2022 | 5 | 8 | Substitution | x = 2 sin u: 7√3/6 − 3/2 |
| Jun 2022 | 6 | 9 | Vectors | Line AB; p = −8 from AC ⊥ AB; area 9√10 |
| Jun 2022 | 7 | 12 | Parametric | Gradient 3 at t = π; tangent y = 3x + 7; meets the curve again |
| Jun 2022 | 8 | 10 | Volume + parts | y = 10xe^(−x/2); density 3.99 g/cm3 |
| Jun 2022 | 9 | 4 | Proof | n2 − 2 is never divisible by 4 |
| Jan 2022 | 1 | 6 | Implicit | xy2 = x2y + 6: tangent at (2, 3) |
| Jan 2022 | 2 | 7 | Binomial | (1 + 4x3)^(1/3); ∛31 |
| Jan 2022 | 3 | 9 | Parametric + partial fractions | x = 3 + 2 sin t, y = 6/(7 + cos 2t): Cartesian form; partial fractions |
| Jan 2022 | 4 | 8 | Rates | Icosahedron: dV/dA; dV/dt at x = 2 |
| Jan 2022 | 5 | 10 | Area (parametric) + substitution | x = √(9 − 4t), y = t3/√(9 + 4t); u = 81 − 16t2 |
| Jan 2022 | 6 | 5 | Proof | k, 1 + 2k, 3 + 3k is not a geometric sequence |
| Jan 2022 | 7 | 8 | Volume + parts | Doorknob: (π/16)∫(x2 − 8x + 16)e^(2x) dx |
| Jan 2022 | 8 | 11 | Vectors | Line AB; the lines do not meet; acute angle |
| Jan 2022 | 9 | 11 | Differential equation | 3 cosec 2x · dy/dx = y(1 + 2 ln y)3, with a signposted derivative |
| Oct 2021 | 1 | 7 | Implicit | 2x − 4y2 + 3x2y = 4x2 + 8: normal at (3, 2) |
| Oct 2021 | 2 | 6 | Differential equation | dy/dx = 4y2/√(4x + 5): y = 1/(7 − 2√(4x + 5)) |
| Oct 2021 | 3 | 8 | Partial fractions | Improper g(x); show g′(x) > 3 |
| Oct 2021 | 4 | 6 | Binomial | (1 − 4x2)^(1/2); √3 ≈ 1.7324 |
| Oct 2021 | 5 | 9 | Parametric | x = 5 + 2 tan t, y = 8 sec2t: gradient; Cartesian; range |
| Oct 2021 | 6 | 7 | Substitution + area | u = 3 + 4 sin x: ln(49/25) − 12/35 |
| Oct 2021 | 7 | 9 | Vectors | Foot X; distance √67; reflection |
| Oct 2021 | 8 | 7 | Parts + volume | ∫x2 ln x dx; volume of y = x ln x |
| Oct 2021 | 9 | 10 | Rates + differential equation | Tank: dh/dt = (12 − 3h)/320; about 208 minutes |
| Oct 2021 | 10 | 6 | Proof | Complete the n3 proof; ∛2 is irrational |
| Jun 2021 | 1 | 7 | Binomial | √(1 + kx): k, A and B; √1.15 |
| Jun 2021 | 2 | 7 | Volume | y = 9/(2x − 3)^1.25 with y = 9 and x = 6: 298π |
| Jun 2021 | 3 | 7 | Rates | Bowl: time to fill 20 s; dh/dt = 96/23 |
| Jun 2021 | 4 | 8 | Substitution + partial fractions | u = √x: 4 ln(14/9) |
| Jun 2021 | 5 | 9 | Implicit | y2 = ye^(−2x) − 3x: tangents meet at R |
| Jun 2021 | 6 | 10 | Parametric + area | x = 2 cos 2t, y = 4 sin t: area 8√2/3; Cartesian; range |
| Jun 2021 | 7 | 10 | Vectors | Unit vector; closest point to O; area √101/2 |
| Jun 2021 | 8 | 9 | Differential equation + parts | dy/dx = 6xe^(−2x)y^(1/3); asymptote |
| Jun 2021 | 9 | 8 | Vectors + proof | c = 3b − 2a; if n2 is a multiple of 3, so is n |
| Jan 2021 | 1 | 7 | Binomial | √(1 − 20x); √5 |
| Jan 2021 | 2 | 5 | Vectors | Angle ABC; parallelogram area |
| Jan 2021 | 3 | 2 | Proof | There is no greatest odd integer |
| Jan 2021 | 4 | 7 | Parametric | Cartesian g(x) = (x − 4)/(3x − 5); range |
| Jan 2021 | 5 | 8 | Substitution | u = 3 + √(2x − 1): p + q ln 2 |
| Jan 2021 | 6 | 9 | Implicit | 4y2 + 3x = 6ye^(−2x): normal at P |
| Jan 2021 | 7 | 7 | Parts + area | ∫e^(2x) sin x dx; area (e^(2π) + 1)/5 |
| Jan 2021 | 8 | 6 | Vectors | Skew for every b ≠ 7 |
| Jan 2021 | 9 | 10 | Volume (parametric) | x = tan θ, y = 2 sin 2θ: 8π2/3 − 2√3π |
| Jan 2021 | 10 | 14 | Partial fractions + differential equation | Tank depth; time to 8 m; long-term depth 5 m |
| Oct 2020 | 1 | 4 | Proof | If n3 is even, n is even |
| Oct 2020 | 2 | 8 | Binomial | (4 − 5x)^(−1/2); k and m |
| Oct 2020 | 3 | 6 | Volume | y = e^(0.5x) − 2: 8π ln 2 − 5π |
| Oct 2020 | 4 | 12 | Parametric | Tangent at B; where it meets the curve again |
| Oct 2020 | 5 | 7 | Parts + area | ∫ln x/x2 dx; area 1 + 2 ln 2 |
| Oct 2020 | 6 | 7 | Implicit | y = x^(sin x) by logs; stationary points |
| Oct 2020 | 7 | 12 | Substitution + partial fractions | ∫3x/√(2x − 1) dx = 16; improper partial fractions |
| Oct 2020 | 8 | 10 | Vectors | Intersection; foot Q |
| Oct 2020 | 9 | 9 | Differential equation | Bacteria; limiting area 900/361 |